C++ implementation to find minimum swaps required to bring all elements less than or equal to k together. Submitted by Vikneshwar GK, on March 04, 2022 Consider an integer array, of size n, and an integer k. The task at hand is to find the minimum number of swa...
题目地址:https://leetcode-cn.com/problems/minimum-swaps-to-group-all-1s-together/ 题目描述 Given a binary array data, return theminimumnumber of swaps required to group all 1’s present in the array together in any place in the array. Example 1: Input: [1,0,1,0,1] Output: 1 Expla...
1classSolution {2func minSwaps(_ data: [Int]) ->Int {3let n:Int =data.count4vars:[Int] = [Int](repeating:0,count:n+1)5foriin1...n6{7s[i] = s[i-1] + data[i-1]8}9varm:Int =s[n]10varret:Int =n11foriinm...n12{13ret = min(ret, m-(s[i]-s[i-m]))14}15ret...
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At last we will return the value of the count and will print that in the main function. Example #include<bits/stdc++.h>usingnamespacestd;// function to get the minimum number of swapsintminSwaps(string str){string temp=str;reverse(temp.begin(),temp.end());// reversing the stringinti...
Given a binary array data, return the minimum number of swaps required to group all 1’s present in the array together in any place in the array. Example 1: Input: data = [1,0,1,0,1] Output: 1 Explanation: There are 3 ways to group all 1's together: ...
Given a binary arraydata, return the minimum number of swaps required to group all1’s present in the array together in any place in the array. Example 1: Input: data = [1,0,1,0,1] Output: 1 Explanation: There are 3 ways to group all 1's together: ...
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To bring the array back to its original form, iterate through the array and divide every element bymaxVal. Print the array. C++ Implementation: #include <bits/stdc++.h>usingnamespacestd;voidrearrangeArray(intarray[],intlength) {// min max pointersintmax=length-1, min=0;//...
intuition: the # of 1s that should be grouped together is the # of 1's the whole array has. every subarray of size ones, need several number of swaps to reach, which is the number of zeros in that subarray. use sliding window, check all the window with the same length n (# of ...