Leetcode力扣 209 | 长度最小的子数组 Minimum Size Subarray Sum 2020年11月05日 07:455743浏览·30点赞·11评论 爱学习的饲养员 粉丝:7.0万文章:46 关注 视频讲解 622:17 Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 84.4万798 ...
Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead. For example, given the array[2,3,1,2,4,3]ands = 7, the subarray[4,3]has the minimal length under the problem c...
双指针 classSolution{public:intminSubArrayLen(ints, vector<int>& nums){intsum=0;intleft=0;intans=INT_MAX;for(inti=0;i<nums.size();i++) { sum+=nums[i];while(sum>=s) { ans=min(ans,i-left+1); sum-=nums[left]; left++; } }returnans==INT_MAX?0:ans; } }; DP classSoluti...
LeetCode_Array_64. Minimum Path Sum (C++) 云计算 目录 1,题目描述 2,思路 3,代码【C++】 4,测试效果 1,题目描述 Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes th...
[leetcode] 209. Minimum Size Subarray Sum Description Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn’t one, return 0 instead.
Can you solve this real interview question? Sum of Subarray Minimums - Given an array of integers arr, find the sum of min(b), where b ranges over every (contiguous) subarray of arr. Since the answer may be large, return the answer modulo 109 + 7. Ex
Question link: https://leetcode.com/problems/minimum-index-sum-of-two-lists/description/ GitHub: https://github.com/ctfu Time complexity: O(n), worse case O(m + n) Space complexity: O(n) 知识 校园学习 课程 编程 每日一题 leetcode hashmap ...
怎么找呢,我们可以使用两个 for 循环来枚举,但这又和第一种暴力求解一样了,所以我们可以换种思路,求 sums[k]-sums[j]>=s 我们可以求 sums[j]+s<=sums[k],那这样就好办了,因为数组sums中的元素是递增的,也就是排序的,我们只需要求出 sum[j]+s 的值,然后使用二分法查找即可找到这个 k。
给你一个二进制字符串s,现需要将其转化为一个交替字符串。请你计算并返回转化所需的最小字符交换次数,如果无法完成转化,返回-1。 交替字符串是指:相邻字符之间不存在相等情况的字符串。例如,字符串"010"和"1010"属于交替字符串,但"0100"不是。 任意两个字符都可以进行交换,不必相邻。
LeetCode 209: Minimum Size Subarray Sum(长度最小的子数组) Q:Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn't one, return 0 instead. ...