Can you solve this real interview question? Minimum Operations to Make the Array Increasing - You are given an integer array nums (0-indexed). In one operation, you can choose an element of the array and increment it by 1. * For example, if nums = [1,2
Runtime:3 ms, faster than68.44%of Java online submissions for Minimum Operations to Make the Array Increasing. Memory Usage:48.6 MB, less than29.23%of Java online submissions for Minimum Operations to Make the Array Increasing. 数据好不好,咱不说,至少一次过了。
1551. Minimum Operations to Make Array Equal You have an arrayarrof lengthnwherearr[i] = (2 * i) + 1for all valid values ofi(i.e.0 <= i < n). In one operation, you can select two indicesxandywhere0 <= x, y < nand subtract1fromarr[x]and add1toarr[y](i.e. performarr[...
每次操作可以同时将一个数字+1 另外一个数字-1,问你操作多少次可以让这个数组里面的数字都变成一样的。 那肯定是把所有数字变成最中间那个数字,最快。二. 代码 基本就是一道小学数学题,自己在纸上写出来规律,得出公式,然后用简单的代码把这个公式写了出来。直接看我的代码,那肯定看不懂意思,因为这是自己得出来...
Given an integern, the length of the array. Returnthe minimum number of operationsneeded to make all the elements of arr equal. Example 1: Input: n = 3 Output: 2 Explanation: arr = [1, 3, 5] First operation choose x = 2 and y = 0, this leads arr to be [2, 3, 4] ...
Can you solve this real interview question? Minimum Increment to Make Array Unique - You are given an integer array nums. In one move, you can pick an index i where 0 <= i < nums.length and increment nums[i] by 1. Return the minimum number of moves to m
publicstaticintminOperations(int[]nums){int cnt=0;int n=nums.length;for(int i=0;i<n-2;i++){if(nums[i]==0){cnt++;nums[i+1]=1-nums[i+1];nums[i+2]=1-nums[i+2];}}if(nums[n-2]!=1||nums[n-1]!=1){return-1;}returncnt;}...
class Solution: def minOperations(self, nums: List[int], k: int) -> int: _xor = k for num in nums: _xor = _xor ^ num res = 0 while _xor != 0: res += 1 _xor &= _xor - 1 return res
from sortedcontainers import SortedList class Solution: def minimumOperations(self, nums: List[int]) -> int: if len(nums) == 1: return 0 even = nums[0::2] odd = nums[1::2] #print(len(nums)) evenc = Counter(even) oddc = Counter(odd) freqe = defaultdict(list) freqo = default...
945. Minimum Increment to Make Array Unique(python) 对于相同的数字不断加1使得与所有的数字不相同。 返回加1的次数。 分析:循环两两比较使得每两个之间不相等,最终得到一个递增序列。 代码:...945. Minimum Increment to Make Array Unique(Leetcode每日一题-2020.03.22) Problem Given an array of ...