You are given an integer arraynumsand an integerx. In one operation, you can either remove the leftmost or the rightmost element from the arraynumsand subtract its value fromx. Note that this modifies the array for future operations. Returnthe minimum number of operations to reducexto exactly...
Java实现 1classSolution {2publicintminOperations(intn) {3intm = n / 2;4if(n % 2 == 1) {5returnm * (m + 1);6}else{7returnm *m;8}9}10} LeetCode 题目总结
You are given an integer arraynums(0-indexed). In one operation, you can choose an element of the array and increment it by1. For example, ifnums = [1,2,3], you can choose to incrementnums[1]to makenums = [1,3,3]. Return the minimum number of operations needed to makenumsstric...
一个房间里有 n 个座位和 n 名学生,房间用一个数轴表示。给你一个长度为 n 的数组 seats ,其中 seats[i] 是第i 个座位的位置。同时给你一个长度为 n 的数组 students ,其中 students[j] 是第j 位学生的位置。 你可以执行以下操作任意次: 增加或者减少第 i 位学生的位置,每次变化量为 1 (也就是将...
LeetCode 1557M 可以到达所有点的最少点数目Minimum Number of Vertices to Reach All Nodes 王几行XING 北京大学 计算机技术硕士 来自专栏 · LeetCode·力扣·300首 1 人赞同了该文章 读题 解法一:入度为0的节点 简单来说,我们要找的是图中所有入度为0的节点,因为只有这些节点不是任何其他节点的目的...
Can you solve this real interview question? Minimum Number of K Consecutive Bit Flips - You are given a binary array nums and an integer k. A k-bit flip is choosing a subarray of length k from nums and simultaneously changing every 0 in the subarray to
AI代码解释 classSolution:defminOperations(self,nums:List[int],x:int)->int:n=len(nums)total=sum(nums)iftotal<x:return-1iftotal==x:returnn target=total-x prefix=0stat={}stat[0]=-1maximum=-1foriinrange(n):prefix+=nums[i]stat[prefix]=iifprefix-targetinstat:maximum=max(maximum,i-stat...
LeetCode:871. Minimum Number of Refueling Stops - Python 问题描述: 871. 最低加油次数 汽车从起点出发驶向目的地,该目的地位于出发位置东面 target英里处。 沿途有加油站,每个station[i] 代表一个加油站,它位于出发位置东面 station[i][0] 英里处,并且有 station[i][1] 升汽油。 假设汽车油箱的容量是...
In one operation, you can either remove the leftmost or the rightmost element from the array nums and subtract its value from x. Note that this modifies the array for future operations. Return the minimum number of operations to reduce x to exactly 0 if it's possible, otherwise, return -...
原题目:https://leetcode-cn.com/problems/minimum-number-of-arrows-to-burst-balloons/ 思路: 首先对数组按照右端点进行排序,每次从右端点射出,就可达到贪心策略。如果起点大于了射箭的位置,数目加一,箭的位置设置为当前气球的右端点。 代码: ...Leet