The sys.maxint constant has been removed from Python 3.0 onward, instead use sys.maxsize. Integers PEP 237: Essentially, long renamed to int. That is, there is only one built-in integral type, named int; but it behaves mostly like the old long type. PEP 238: An expression like 1/2 ...
Find the minimum element. You may assume no duplicate exists in the array. 这是LeetCode 上的一道算法题,题意是一个已经排序的数组,截断后重新拼接,找出数组中最小的数字。 这道题目用 Python 来实现的话太简单了。代码如下: classSolution:#@param num, a list of integer#@return an integerdeffindMin...
Python 代码 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None # 黄哥Python培训 黄哥所写 class Solution: def getMinimumDifference(self, root: TreeNode) -> int: if root is None: return 0 ...
代码(Python3) class Solution: def minWindow(self, s: str, t: str) -> str: m: int = len(s) # count[ch] 表示滑动窗口 [l, r) 中字母 ch 还需出现的次数。 # 初始化为 t 中每个字母的出现次数 count: Dict[int, int] = Counter(t) # remain 表示滑动窗口 [l, r) 中还需出现的不...
1 #include<iostream> 2 #include<cstring> 3 #include<cstdlib> 4 #include<cstdio> 5 using namespace std; 6 const int maxn=1000050; 7 int next[maxn]; 8 char str[maxn]; 9 int main() 10 { 11 int i,j; 12 while(scanf("%s",str)!=EOF) 13 { 14 j=-1; 15 i=0; 16 next[...
public int minimumDeleteSum(String s1, String s2) { dp = new int[s1.length() + 1][s2.length() + 1]; return go(s1.toCharArray(), s2.toCharArray(), s1.length() - 1, s2.length() - 1); } int[][] dp; int go(char[] cs1, char[] cs2, int p1, int p2) { if (dp[p1...
Remove Python 3.8 support (EOL). Bump numpy to >=2 Mar 14, 2025 numpy_minmax Optimize int16 processing, with support for AVX, but not AVX512 Aug 1, 2024 scripts Optimized processing for 1d strided arrays (#11) Jan 15, 2024 tests ...
代码二 (python) 用了二分法来缩小空间,(腾讯面试被问到,当时觉得自己没写好,所以结束后重新写一下,发现效率没有双指针高) class Solution: def minSubArrayLen(self, s: int, nums: List[int]) -> int: n=len(nums) sums=[0]*(n+1) for i in range(1,n+1): ...
int minDiff = Integer.MAX_VALUE; TreeNode prev = null; public int getMinimumDifference(TreeNode root) { inOrder(root); return minDiff; } public void inOrder(TreeNode root){ if(root == null){ return; } inOrder(root.left); if(prev !=null) minDiff= Math.min(minDiff, root.val -...
}intmy(intcur,intx,inty,intz) {if(cur==1) {returnx; }// meoization, dont compute what's already computedif(dp[cur]!=-1)returndp[cur];if(cur%2==0) {//for even ndp[cur]=minimum(x+my(cur-1, x, y, z), z+my(cur/2, x, y, z)); ...