一、题目描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二、分析 这题难度有,因为他默认的是数组中所有的元素是不同的。只...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 这道题目就是Find Minimum in Rotated Sorted Array的增强版,在数组中增加了重复的元素。 具体的解法...
Find Minimum in Rotated Sorted Array I Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二分迭代法 复杂度 时间O(N) 空...
【LeetCode】154. Find Minimum in Rotated Sorted Array II (cpp),程序员大本营,技术文章内容聚合第一站。
Find Minimum in Rotated Sorted Array II 理论上这题应该也用二分法,碰到起点终点相同的情况就只能进行遍历,但是那样代码会更复杂并且效率上并不见得提高多少,所以这里我直接采用遍历的方法。 实现代码: javapublic class Solution { public int findMin(int[] num) { ...
问题描述: Suppose an array sorted in ascending(升序) order is rotated at some pivot(枢轴; 中心点) unknown to you beforehand(提前,事先). (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You... 查看原文 LeetCode154.寻找旋转排序数组中的最小值 ...
Java program to find minimum element in a sorted and rotated array : If you want to practice data structure and algorithm programs, you can go through data structure and algorithm interview questions. In this post, we will see how to find minimum element in sorted and rotated array. Problem...
Here, we are going to find the solution to find the minimum in rotated sorted array with C++ implementation.
Follow up for “Find Minimum in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. ...
Find the minimum element. The array may contain duplicates. 解题思路: 参考Java for LeetCode 081 Search in Rotated Sorted Array IIJAVA实现如下: 1 2 3 4 5 6 7 8 9 10 11 12 13 publicintfindMin(int[] nums) { intleft =0, right = nums.length -1, res = nums[0]; ...