直接翻译题目即可,分两步走,第一,找到数组arr中的最小绝对差值,通过排序来完成,借助Arrays的sort方法实现,因为绝对值差最小的两个数肯定是相邻越近越小。第二,再次遍历arr数组,将绝对值差等于最小绝对值差的两个元素添加到结果list中去。 publicList<List<Integer>>minimumAbsDifference(int[] arr){ Arrays.sort...
https://discuss.leetcode.com/topic/80896/my-solution-using-no-recursive-in-order-binary-tree-iteration https://discuss.leetcode.com/topic/80823/two-solutions-in-order-traversal-and-a-more-general-way-using-treeset/2 https://discuss.leetcode.com/topic/80916/java-no-in-order-traverse-solution-...
第二,再次遍历arr数组,将绝对值差等于最小绝对值差的两个元素添加到结果list中去。 publicList<List<Integer>>minimumAbsDifference(int[]arr){Arrays.sort(arr);intmin=Integer.MAX_VALUE,len=arr.length;for(inti=1;i<len;i++){min=Math.min(min,arr[i]-arr[i-1]);}List<List<Integer>>result=newAr...
题目地址:https://leetcode.com/problems/minimum-absolute-difference-in-bst/#/description 题目描述 Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The min...
Loading...leetcode.com/problems/minimum-absolute-difference-in-bst/ 1、读题,Given a binary search tree with non-negative values, find the minimumabsolute differencebetween values of any two nodes. 节点的值都是non-negative , 求任意two nodes, 之间最小绝对值。
public: vector<vector<int>> minimumAbsDifference(vector<int>& arr) { sort(arr.begin(),arr.end()); vector<vector<int>> arrdiff; int arr_len = arr.size(); int minsize = INT_MAX; for(int i = 1;i < arr_len ; i++) {
中序遍历,方法跟minimum-absolute-difference-in-BST一样。 代码 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
https://leetcode.com/problems/minimum-absolute-difference-in-bst/description/ 解题思路: 相同的解题思路因为left < root < right, 因此用inorder travesal 代码: class Solution { int diff = Integer.MAX_VALUE; TreeNode pre = null; public int minDiffInBST(TreeNode root) { ...
class Solution { public: static constexpr int mod = 1'000'000'007; int minAbsoluteSumDiff(vector<int>& nums1, vector<int>& nums2) { vector<int> rec(nums1); sort(rec.begin(), rec.end()); int sum = 0, maxn = 0; int n = nums1.size(); for (int i = 0; i < n; i+...
class Solution { int mod = (int)1e9+7; public int minAbsoluteSumDiff(int[] nums1, int[] nums2) { int n = nums1.length; int[] sorted = nums1.clone(); Arrays.sort(sorted); long sum = 0, max = 0; for (int i = 0; i < n; i++) { int a = nums1[i], b = nums2...