第二种解法还可以再优化下,将递归方法内置,同时min初始值为int类型的最大值,而不是第二种解法的0,可以省去一步判断。 Integerprev2=null;intmin2=Integer.MAX_VALUE;publicintgetMinimumDifference3(TreeNode root){if(root ==null) {returnmin2; } getMinimumDifference3(root.left);if(prev2 !=null) { ...
The minimum absolute difference is 1, which is the difference between 2 and 1 (or between 2 and 3). Note: There are at least two nodes in this BST. 题意及分析:给出一颗二叉搜索树(节点为非负),要求求出任意两个点之间差值绝对值的最小值。题目简单,直接中序遍历二叉树,得到一个升序排列的lis...
1 题目描述 题目链接:https://leetcode-cn.com/problems/minimum-absolute-sum-difference/添加链接描述 给你两个正整数数组 nums1 和 nums2 ,数组的长度都是 n 。 数组 nums1 和 nums2 的 绝对差值和 定义为所有 |nums1[i] - nums2[i]|(0 <= i < n)的 总和(下标从 ...力扣...
题目地址:https://leetcode.com/problems/minimum-absolute-difference-in-bst/#/description 题目描述 Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The min...
Given a Binary Search Tree (BST) with the root node root, return the minimum difference between the values of any two different nodes in the tree. Example: Input: root = [4,2,6,1,3,null,null] Output: 1 Explanation: Note that root is a TreeNode object, not an array. The given ...
#include <bits/stdc++.h> using namespace std; // Function to find the minimum value // in sorted and rotated array int findMin(int array[], int low, int high) { // if array is not rotated if (high < low) return array[0]; // if array contains only one element if (hig...
It can be solve by storing node value in an array and then calculating the minimum difference by native approach. But i was trying to solve it using DFS. I have tried to see discussion of many solver who tried DFS but not getting out the actually how it has been solved by DFS. Can ...
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Consider an integer array, of sizen, and an integerk. The task at hand is to find the minimum number of swaps that are required to bring the array elements, that are lesser than or equal tok, together. Example Input: array[]= {2, 5, 4, 1, 6, 4} ...
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