next return list class Solution: def mergeTwoLists(self, head1, head2): if not head1: # 如果head1为空,直接返回head2 return head2 if not head2: # 如果head2为空,直接返回head1 return head1 pre = ListNode(0) # 使用哑结点简化操作 head = pre while head1 and head2: if head1.val ...
需要遍历 list2 中的全部 O(|list2|) 个结点 空间复杂度:O(1) 只需要维护常数个额外变量 代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list...
https://discuss.leetcode.com/topic/6187/14-line-clean-c-solution 该解法也是先初始化链表,只不过这一步是通过链表的构造函数来完成的。初始化后,再定义一个链表指针,让它指向该链表的头结点,之后的步骤就和上面的解法一样了。 /** * Definitionforsingly-linked list. * struct ListNode { *intval; * L...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. » Solve this problem [Thoughts] 简单的实现,也没什么可说的。 [Code] 1:ListNode*mergeTwoLists(ListNode*l1,ListNode*l2){ 2:if(l1==NULL)retur...
leetcode 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4...
LeetCode-Java-21. Merge Two Sorted Lists 题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4
1. Description Merge Two Sorted Lists 2. Solution /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution{public:ListNode*mergeTwoLists(ListNode*l1,ListNode*l2){ListNode*ptrFirst=l1...
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4,1->3->4Output:1->1->2->3->4->4 ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 翻译:合并两个排好序的链列,并将其作为新链表返回。新链表应通过将前两个列表的节点拼接在一起。
Here's a list of 30 coding interview patterns, each with one or two example LeetCode problems:1. Sliding WindowProblem 1: Minimum Size Subarray Sum Problem 2: Longest Substring Without Repeating Characters2. Two PointersProblem 1: 3Sum Problem 2: Container With Most Water...