代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: # 使用一个哨兵...
leetcode Merge Two Sorted Lists python #Definition for singly-linked list.#class ListNode(object):#def __init__(self, x):#self.val = x#self.next = NoneclassSolution(object):defmergeTwoLists(self, l1, l2):""":type l1: ListNode :type l2: ListNode :rtype: ListNode"""ifl1==None:ret...
s=Solution()#融合两个链表q=s.mergeTwoLists(l1,l2)
# class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def mergeTwoLists(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ head=ListNode(0) cur=head while l1 or l2: if not l2 or (l1...
Example 1:Concatenating two lists 示例1:连接两个列表 l1=[1,2,3] l2=[4,5,6] l3=l1+l2 print (l3)#Output:[1, 2, 3, 4, 5, 6] 1. 2. 3. 4. Example 2:Concatenating two or more lists 示例2:连接两个或更多列表 l1=[1,2,3] ...
Python代码: # Definition for singly-linked list. class ListNode(object): def __init__(self, x): self.val = x self.next = None class Solution(object): def mergeTwoLists(self, l1, l2): """ :type l1: ListNode :type l2: ListNode ...
You problem is a pretty basic Python problem: "Iterate trough two lists in parallel. Add the items of both list sequentially to the list of results." Thanks a lot! I can imagine that Python requires a different way of thinking/solving problems. And I already see that some tasks are way...
Merge items from 3 to 7 in the said List: ['a', 'b', 'c', 'defg'] Flowchart: For more Practice: Solve these Related Problems: Write a Python program to merge list items between two given index positions and replace them with the concatenated result. ...
You are given the heads of two sorted linked lists list1 and list2. Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists. Return the head of the merged linked list. Example 1: 代码语言:javascript 代码运行次数:0 运行...
用一个大小为K的最小堆(用优先队列+自定义降序实现)(优先队列就是大顶堆,队头元素最大,自定义为降序后,就变成小顶堆,队头元素最小),先把K个链表的头结点放入堆中,每次取堆顶元素,然后将堆顶元素所在链表的下一个结点加入堆中。 代码语言:javascript ...