next return list class Solution: def mergeTwoLists(self, head1, head2): if not head1: # 如果head1为空,直接返回head2 return head2 if not head2: # 如果head2为空,直接返回head1 return head1 pre = ListNode(0) # 使用哑结点简化操作 head = pre while head1 and head2: if head1.val ...
因为每次调用递归都会去掉list1或者list2的头节点(直到至少有一个链表为空),函数mergeTwoList至多只会递归调用每个节点一次,时间复杂度取决于合并后的链表长度。 空间复杂度:O(n+m),其中 n 和 m 分别为两个链表的长度。递归调用mergeTwoLists函数时需要消耗栈空间,栈空间的大小取决于递归调用的深度。结束递归调用...
res.next= l2;//这里是res.next,不是res}returnhead.next;//因为初始化时候设置初始节点为0,l1和l2的节点从第二个开始}//递归publicListNode mergeTwoLists(ListNode l1, ListNode l2){if(l1 ==null){returnl2; }if(l2 ==null){returnl1; }if(l1.val <l2.val){ l1.next=mergeTwoLists(l1.next,l2...
*@returnListNode */functionmergeTwoLists($list1,$list2){$res=null;$this->merge($list1,$list2,$res);return$res; }functionmerge($l1,$l2, &$node){if(null==$l1&&null==$l2)return;$node=newListNode();if(null==$l1) {$node->val =$l2->val;$this->merge(null,$l2->next,$node->...
Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. Example 1: Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4] Example 2: ...
LeetCode第21题 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 ...
Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing(拼接) together the nodes of the first two lists. The sorted list is in ascending order. typedef struct _ListNode { int val; struct _ListNode *next;...
Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 # Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defmergeTwoLists(self,l1,l2):"""
l1.next=self.mergeTwoLists(l1.next,l2)returnl1orl2 以上两个方法使用了迭代的思想,LeetCode处理linked list更常用的方法是指针。在新list前加入一个dummy head。然后使用一个指针来修改list。 # Definition for singly-linked list.# class ListNode(object):# def __init__(self, x):# self.val = x#...
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