Note:You may assume that A has enough space (size that is greater or equal tom+n) to hold additional elements from B. The number of elements initialized in A and B aremandnrespectively. 解法一:从前往后,小的排最前。每次插入一个B,A需要整体后移。 classSolution {public:voidmerge(intA[],i...
You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. 1publicclassSolution {2publicvoidmerge(int[] nums1,intm,int[] nums2,intn) {3if(n == 0)return;...
到这里我们就明白了为何要使用 nums1[:]。这里 sorted() 函数返回的必然是一个新的对象,因此我们需要 nums1[:], 而 [] 也代表一个新的 list 对象,我们需要用 nums1[:] = []。 ps: 如果没有就地修改的要求,则用 nums1 也是完全正确的。 因此对思路一进行代码修改,顺利通过 1 class Solution: 2 def...
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn 按照归并排序的惯性思...
class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { int i=; int j=; for(; j<n;j++){ for(; i<m+j;i++){ if(nums2[j]<nums1[i]) break; } if(i<m+j){ nums1.insert(nums1.begin()+i,nums2[j]); nums1.pop_back(); } ...
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional...
class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ # i/j 分别表示 nums1/nums2 中还未使用的最大数的下标 i, j = m - 1, n - 1 # k 表示 nums1 中下一个该...
The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ...
Write a C program to merge two sorted array elements into a single array.Problem Solution1. Create two arrays of some fixed size and define their elements in sorted fashion. 2. Take two variables i and j, which will be at the 0th position of these two arrays. 3. Elements will be ...
www.lintcode.com/en/problem/merge-sorted-array/ 【题目解析】 直观思路显然是双指针i, j同时扫描A, B,选min(A[i], B[j])作为下一个元素插入。但是只能利用A后面的空间来插入,这样就很不方便了。 反向思路,merge后的数组一共有m+n个数。i, j从A, B尾部扫描,选max(A[i], B[j])插入从m+n起...