CodeForces 873D Merge Sort 构造 分治 题意 给出一个归并排序的算法mergesortmergesort,如果对于当前区间[l,r)[l,r)是有序的,则函数直接返回。 否则会分别调用mergesort(l,mid)mergesort(l,mid)和mergesort(mid,r)mergesort(mid,r),其中mid=⌊l+r2⌋mid=⌊l+r2⌋ 最后合并左右两个子区间 下面请...
codeforces 873 D. Merge Sort(分治) 题目链接:http://codeforces.com/contest/873/problem/D 题解:这题挺简单的,除了一开始算作是调用到一次,然后每次执行操作时都会调用2次,所以最多调用几次就很好算了,而且只有奇数调用次数才合理。然后就是类似分治的思想,每次dfs二分过去,发现调用次数不够就交换mid和mid-1...
Sometimes I encounter a type of range queries that I don't know how to do using segment tree, so I use a merge sort tree instead. It can answer queries in O(log2n)O(log2n). I decided to share this because it can be useful to many in contests. First, we know that a node in...
I am facing a runtime issue in my code.Can anyone help me with my code: My code link: https://pastebin.com/qCC4GsPS. Just check the merge and mergesort function in this link.#merge sort, #linked list -6 rsudhanshu138 4 years ago 0 ...
Educational Codeforces Round 30-D-Merge Sort(瞎搞),题意:给你n和k,问你能否构造出一个长为n的全排列,使得按照归并排序的执行规则,正好调动k次归并排序函数使得原排列变成递增排列。题解:我们知道对于递减的排列,需要调用归并函数最多次,因此我们可以初始化数组
"io" "sort" )// github.com/EndlessCheng/codeforces-go func CF580B(_r io.Reader, out io.Writer) { in := bufio.NewReader(_r) var n, d, l int Fscan(in, &n, &d) a := make([]struct{ x, y int }, n) for i := range a { Fscan(in, &a[i].x, &a[i].y) ...
归并排序,我们就叫这个函数 `merge_sort` 吧,按照我们上面说的,要明确该函数的职责,即 **对传入的一个数组排序**。OK,那么这个问题能不能分解呢?当然可以!给一个数组排序,不就等于给该数组的两半分别排序,然后合并就完事了。 6 changes: 3 additions & 3 deletions 6 docs/basic/greedy.md Original file ...
Dragons http://codeforces.com/problemset/problem/230/A Dragons time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Kirito is stuck on a level of the MMORPG he is playing now. To move on in the game, he's got to defeat alln...
查看题目 登录后递交 讨论 题解 文件 统计 信息 ID 3434 时间 1000ms 内存 256MiB 难度 10 标签 math probabilities *3200 递交数 0 已通过 0 上传者 Hydro
847B - Preparing for Merge Sort 思路:前面的排序的最后一个一定大于后面的排序的最后一个。所以判断要不要开始新的排序只要拿当前值和上一个排序最后一个比较就可以了。 代码: #include<bits/stdc++.h>usingnamespacestd;#definell long long#definepb push_back#definemem(a,b) memset(a,b,sizeof(a))...