88. Merge Sorted Array 思路一:把nums2直接复制到nums1中,然后sort,但是你会发现地址在sort时返回的地址已经发生改变,所以这种解法是不对的。 class Solution: def merge1(self,nums1,m,nums2,n): print(id(nums1)) len1 = len(nums1) len2 = n for i in range(len1-len2,len1): nums1[i] ...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. 合并两...
k:int=m+n-1# 如果 nums2 中还有数字,则继续向 nums1[k] 填充当前最大的数whilej>=0:ifi>=0andnums1[i]>nums2[j]:# nums1 和 num2 中都还有数字,且 nums1[i] > nums2[j] ,# 则将 nums1[i] 放到 k 处nums1[k]=nums1[i]i-=1else:# 此时有两种情况,都需要将 nums2[j] 放到 k ...
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn 按照归并排序的惯性思...
88. Merge Sorted Array 思路一:把nums2直接复制到nums1中,然后sort,但是你会发现地址在sort时返回的地址已经发生改变,所以这种解法是不对的。 class Solution: def merge1(self,nums1,m,nums2,n): print(id(nums1)) len1 = len(nums1) ...
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional...
88. Merge Sorted Array Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: The number of elements initialized innums1andnums2aremandnrespectively. You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elem...
给定两个以非递减序列排序的数组nums1和nums2,m和n分别表示取nums1和nums2的元素个数。 以非递减序列合并两个数组,将最终的结果存储到 nums1 中,为了适应这一点,nums1 的长度为 m+n。 解析 在不使用额外空间的情况下,对于一个有序列表使用插入排序可以完成。但是时间复杂度会提高,考虑这两个有序数组,本来...
88 Merge Sorted Array 给定两个有序整数数组 nums1 和 nums2,将nums2合并到nums1中,使nums1称为一个有序数组。 初始化nunms1和nums2的元素数量分别为 m 和 n,假设 nums1的空间大小等于m + n,这样它有足够的空间保存来自nums2的元素。 合并两个有序数组常规方法...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. ...