}// This function takes an array of// arrays as an argument and All// arrays are assumed to be sorted.// It merges them together and// prints the final sorted output.staticvoidmergeKSortedArrays(int[][] arr,intk){ MinHeapNode[] hArr =newMinHeapNode[k];intresultSize=0;for(inti=0...
代码如下: classSolution:#@param {int[][]} arrays k sorted integer arrays#@return {int[]} a sorted arraydefmergekSortedArrays(self, arrays):importheapqifnotarrays:return[] heap=[] indexs= [0] *len(arrays)foriinxrange(len(arrays)):ifarrays[i]: heap.append((arrays[i][0],i)) res=...
完整代码 import heapq class Solution: # @param {int[][]} arrays k sorted integer arrays # @return {int[]} a sorted array def mergekSortedArrays(self, arrays): # Write your code here result = [] heap = [] for index, array in enumerate(arrays): if len(array) == 0: continue hea...
Merge K Sorted Arrays This problem can be solved by using a heap. The time is O(nlog(n)). Given m arrays, the minimum elements of all arrays can form a heap. It takes O(log(m)) to insert an element to the heap and it takes O(log(m)) to delete the minimum element. 1classRe...
(index, id+1, lists.get(index).get(id+1)));37}38res.add(pa.value);39}4041returnres;42}4344/**45*@paramargs46*/47publicstaticvoidmain(String[] args) {48//TODO Auto-generated method stub49List<Integer> l1 = Arrays.asList(1,2,2,3,6);50List<Integer> l2 = Arrays.asList(1,4...
486. Merge K Sorted Arrays Description Givenksorted integer arrays, merge them into one sorted array. Example Example 1: Input: [ [1, 3, 5, 7], [2, 4, 6], [0, 8, 9, 10, 11] ] Output: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]...
4. 寻找两个正序数组的中位数 Median of Two Sorted Arrays 力扣 LeetCode 题解 程序员写代码 293 1 312. 戳气球 Burst Balloons 力扣 LeetCode 题解 程序员写代码 336 0 216. 组合总和 III Combination Sum III 力扣 LeetCode 题解 程序员写代码 160 0 78. 子集 Subsets 力扣 LeetCode 题解 程序...
0004. Median of Two Sorted Arrays 0005. Longest Palindromic Substring 0006. Zig Zag Conversion 0007. Reverse Integer 0008. String to Integer Atoi 0009. Palindrome Number 0011. Container With Most Water 0012. Integer to Roman 0013. Roman to Integer 0014. Longest Common Prefix 0015.3 Sum 0016.3...
→ invariant: a[1..k] in final position 算法实现: #include<stdio.h>//defining a function to merge 2 sorted arrays//note that the 2 arrays will be contained in a single array//as the left and right partvoidmerge(intarr[],intstart,intmid,intend) ...
# Special considerations:iflen(nums1)==0orlen(nums2)==0:returnNone# ParametersmaxHeap=[]ans=[]# Traverse the arrays and construct heapfornum1innums1:fornum2innums2:iflen(maxHeap)==k:# Compare sumsifnum1+num2<-maxHeap[0][0]:heapq.heapreplace(maxHeap,(-(num1+num2),[num1,num2...