## LeetCode 21 合并链表 ## 引用官方代码,定义结点类 class ListNode: def __init__(self, x): self.val = x self.next = None 将数组转换为链表,也可以理解为链表的创建(官网不给出): ## 将给出的数组,转换为链表 def linkedlist(list): head = ListNode(list[0]) ## 列表的第一个元素。这里...
当list1 和 list2 均还有结点时,取它们中较小的头结点放入结果链表中,然后不断循环。 最后当其中一个链表为空时,将另一个链表剩余的部分全部插入结果链表尾部即可。 进阶: LeetCode 23: 合并 k 个有序链表 LeetCode 148: 对无序链表排序 时间复杂度:O(|list1| + |list2|) 需要遍历 list1 中的全部 ...
LeetCode题解之Merge Two Sorted Lists 1、题目描述 2、题目分析 题目要求合并有序的两个链表,要求不能额外申请空间。 3、代码 1ListNode* mergeTwoLists(ListNode* l1, ListNode*l2) {2if( l1 == NULL )returnl2;3if( l2 == NULL )returnl1;4if( l1 == NULL && l2 == NULL )returnNULL;5ListNode...
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Exam
LeetCode-cn Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. AI检测代码解析 Example 1: Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4] ...
leetcode 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Seen this question in a real interview before? Yes
合并两个有序链表 题目描述: 将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。 示例 解题思路: 简单考察对链表的使用 首先先创建一个虚拟头结点head 因为l1,l2两个链表都已经是从小到大排序完成,所以只要判断当前两个链表
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list ...
23. Merge k Sorted Lists Mergeksorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input:[ 1->4->5, 1->3->4, 2->6 ]Output:1->1->2->3->4->4->5->6 思路: 合并k个有序链表,采用分治的思想,时间复杂度O(nlogk) ...
After merging the accounts, return the accounts in the following format: the first element of each account is the name, and the rest of the elements are emailsin sorted order. The accounts themselves can be returned inany order. Example 1: ...