Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: The number of elements initialized innums1andnums2aremandnrespectively. You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. Example: ...
next pre.next = head1 if head1 else head2 return head.next2.3 解法二:递归 ## 解法二:递归 Recursion class Solution: def mergeTwoLists(self, head1, head2): ## head1 和 head2 头结点指代两个链表 ## 递归的 base,结束条件 if head1 is None: return head2 elif head2 is None: return ...
题目思路: 这道题目很简单,首先构造一个新的链表,比较两个链表的指针指向的节点的值大小,将值较少的节点放到新链表中,并将指针位置往后移动一位,直到某个链表为空之后,把剩下的链表全部放到新的链表中就可以了。时间复杂度是(O(m+n)) 代码(python): View Code 转载请注明出处:http://www.cnblogs.com/chr...
代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]: # 使用一个哨兵...
Merge Two Sorted Lists 二、解题 两个有序链表的排序。 三、尝试与结果 classSolution(object):defmergeTwoLists(self,l1,l2):ret=ListNode(0)ifl1==None:returnl2ifl2==None:returnl1ifl1.val<l2.val:ret=l1 ret.next=self.mergeTwoLists(l1.next,l2)else:ret=l2 ...
Same as the problem - merge two sorted arrays. Linear time complexity. /** * Definition of Interval: * public classs Interval { * int start, end; * Interval(int start, int end) { * this.start = start; * this.end = end; * } * } */ public class Solution { /** * @param li...
题目地址:https://leetcode.com/problems/merge-sorted-array/description/ 题目描述 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively. ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并两个有序链表 /** * Definition for singly-linked list. * struct ListNode { * int val; ...
After that, the merge function comes into play and combines the sorted arrays into larger arrays until the whole array is merged. MergeSort(A, p, r): if p > r return q = (p+r)/2 mergeSort(A, p, q) mergeSort(A, q+1, r) ...
Combine:Merge the two sorted subsequences to produce the sorted answer. Merge_sort函数相当于divide, Merge_sort(A, p, q)是对左边递归分组, Merge_sort(A,q+1, r)是对右边递归分组。一直递归到每组只剩一个元素(有序,conquer)就开始合并(combine)。即分完之后是治,治后是合。合并的函数是Merge(A, ...