leetcode4. Median of Two Sorted Arrays 了。(可见leetcode好像并没有对时间进行控制)。 另一种方法: 该问题换成另一种说法就是:寻找两个数组中第K小的数字,这里K=(m+n)/2。首先假设数组A和B的元素个数都大于k/2,我们比较A[k/2-1]和B[k/2-1]两个元素,这两个元素分别表示A的第k/2小的元素和...
代码# Go packageleetcodefuncfindMedianSortedArrays(nums1[]int,nums2[]int)float64{// 假设 nums1 的长度小iflen(nums1)>len(nums2){returnfindMedianSortedArrays(nums2,nums1)}low,high,k,nums1Mid,nums2Mid:=0,len(nums1),(len(nums1)+len(nums2)+1)>>1,0,0forlow<=high{// nums1: …...
Since there is such an important conclusion, we can safely drop the first k/2 element in A, which are definitaly smaller than k-th element in the union of A and B. This is also true for the A[k/2-1] > B[k/2-1] condition, which we should drop the elements in B. When A[...
[2,3], the median is(2 + 3) / 2 = 2.5 Design a data structure that supports the following two operations: void addNum(int num) - Add a integer number from the data stream to the data structure. double findMedian() - Return the median of all elements so far. Example: addNum(1)...
238.product-of-array-except-self.md 239.sliding-window-maximum.md 24.swapNodesInPairs.md 240.search-a-2-d-matrix-ii.md 26.remove-duplicates-from-sorted-array.md 279.perfect-squares.md 283.move-zeroes.md 295.find-median-from-data-stream.md 3.longestSubstringWithoutRepeatingCharacters.md 301...
AtCoder Regular Contest 089 C - Traveling Problem StatementAtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0,0) at time 0, then for each i between 1 and N (inclusive), he will visit poi......
SpiralMatrix.py SumOfSubarrayMinimums.py SurfaceAreaOf3DShapes.py SurroundedRegions.py ThirdMaximumNumbers.py ThreeSum.py TopKFrequentElements.py TwoSumIIAlreadySorted.py max_increase_to_keep_city_skyline.py two_sum.py BFS DFS DP Design
2. When k is 1(when A and B are both not empty), we return the smaller one of A[0] and B[0] 3. When A[k/2-1] = B[k/2-1], we should return one of them In the code, we check if m is larger than n to garentee that the we always know the smaller array, for codi...