The representation obtained is then compared with results already known for the mean and the median, the two extreme cases of the Winsorized mean.doi:10.1002/nav.3800210314Stephen A. Book——: Large deviations of the Winsorized mean of an exponential distribution, Nav. Res. Log. Quart. 21 ...
The results are then extended to the estimation of the parameters of the Weibull distribution.doi:10.1080/00224065.1998.11979829Shapiro Samuel S.Gulati SnehJournal of Quality TechnologyShapiro, S. S. and Gulati, S. (1998). Estimating the mean of an exponential distribution from grouped observations...
and Hewette, J., (1973), “ Double sample test for hypotheses about the mean of an Exponential distribution,” Technometrics, 15, 187-190. :Bulgre n, W G., Hewet , J. E., Double sample tests for hypotheses about the mean of an exponential distribution, Technometrics, 1973, 15(1):...
摘要: In this note it is shown how the methodology of the Zeigler and Tietjen double sample test for testing a hypothesis about the variance of a normal distribution can be used to construct double sample tests for testing hypotheses about the mean of an exponential distribution....
The mean of the exponential distribution equals the mean of the Poisson distribution only when the former distribution has a mean equal to:A.1.0.B.0.50.C.0.25.D.any value smaller than 1.0.的答案是什么.用刷刷题APP,拍照搜索答疑.刷刷题(shuashuati.com)是专业
Large deviations of the winsorized mean of an exponential distribution An asymptotic representation for large deviation probabilities of the Winsorized mean of a sequence of independent, identically distributed exponential random variables is derived. The Winsorized mean, a linear combination of exponenti...
48 Quantitative estimates for the size of an intersection of sparse automatic sets 41:09 A new explicit bound for the Riemann zeta function 52:30 An explicit error term in the prime number theorem for large x 35:49 An invitation to the algebraic geometry over idempotent semirings - Lecture 1...
Using the definition, compute the mean and variance of an exponential distribution. X is a normal random variable with standard deviation 5. If Pr(X less than 30) = .8413, what is the mean of X? Assume the random variable X is normally distributed with mean 50 an...
This article derives confidence intervals based on the likelihood-ratio-test approach by assuming (1) a normal distribution (normal algorithm) and (2) an exponential distribution (exponential algorithm). Because the error population distribution is usually unknown, it is important to study the ...
time-sequential proceduretotal life under testIn the context of a life testing problem, a time-sequential procedure for estimating the mean of an exponential distribution is proposed and is shown to be asymptotically risk-efficient. Asymptotic properties of the stopping number, stopping time and the...