The concepts of mean position and true position are also valid for artificial earth satellites. Because, however, the motion of earth satellites relative to the observer lacks a component equal to the velocity of the earth in its orbital motion around the sun (this velocity is responsible for ...
math_ops.reduce_sum(math_ops.square(embeddings_positive),1)) l2loss = math_ops.multiply(0.25* reg_lambda, reg_anchor + reg_positive, name='l2loss')# Get per pair similarities.similarity_matrix = math_ops.matmul( embeddings_anchor, embeddings_positive, transpose_a=False, transpose_b=True)#...
L2 regularization term on the embedding vectors. print_losses: Boolean. Option to print the xent and l2loss. Returns: npairs_loss: tf.float32 scalar. """ # pylint: enable=line-too-long # Add the regularizer on the embedding. reg_anchor = math_ops.reduce_mean( math_ops.reduce_sum(...
读下图，完成下列问题。 （1）在图1中标出地球自转方向。 （2）图1所示为北半球___（节气）。此时，地球位于图2中的___位置附近， 公转速度 较___（快、慢）。 （3）A、B两点相比，自转线速度较大的是___
Many of the existing regression based methods use a Eu- clidean loss (L2 loss), which penalizes the differences be- tween the estimated ages and the ground-truth ages. How- ever, this type of loss defined based on a single image does not explicitly make use of the ordinal relationship ...
1). A reversed experiment, in which the last part of the period for which there is reanalysis data was used for learning and the first period was used for validation, also demonstrated improvement relative to the simple average. In addition, out-of-sample tests were performed in which one ...
1b–d), relative to the observed climatology simulation (Fig. 1a). The Atlantic mean state bias appears to have somewhat stronger effect on the SST response of the eastern Pacific (Fig. 1e), while the varying SST and surface wind stress responses in the central Pacific tends to be more ...
VOE 是一种用于评估分割算法准确性的指标,全称为 Volume Overlap Error。它表示分割结果与真实分割结果之间的体积重叠比例。VOE 越小,表示分割算法的准确性越高。 RVD 全称为 Relative Volume Difference,是一种用于评估分割算法准确性的指标。它用于计算分割结果与真实分割结果之间的相对体积误差。
Here, L2-error designates to the square root of the value below, Ne ∆t (r((n − 1)t) − r¯n)2 , n=1 where r(t) denotes the solution to (15), Ne is the largest positive integer satisfying Ne∆t ≤ te, and the value of r¯n is zero for any iteration after ...
Regarding the dependence ofβhon the mean thermocline depth, because it is difficult to find the difference in the mean thermocline depth between 1-month to 6-month lead times in Fig.5, the mean thermocline depth bias does not seem to be responsible for the thermocline slope response error. ...