classSolution{ classNode{ Nodeleft=null; Noderight=null; } Noderoot=newNode(); staticfinalintHIGH_BIT=30; publicintfindMaximumXOR(int[] nums){ intn=nums.length; intx=0; for(inti=1; i < n; i++) { add(nums[i -1]); x = Math.max(x, check(nums[i])); } returnx; } public...
classSolution {public:intfindMaximumXOR(vector<int>&nums) {intres=0,mask=0;for(inti=31;i>=0;i--){ mask|=(1<<i);set<int>st;for(inta:nums){ st.insert(a&mask); }inttemp=res|(1<<i);for(intnum:st){if(st.count(temp^num)){ res=temp;break; } } }returnres; } };...
Can you solve this real interview question? Maximum XOR of Two Numbers in an Array - Given an integer array nums, return the maximum result of nums[i] XOR nums[j], where 0 <= i <= j < n. Example 1: Input: nums = [3,10,5,25,2,8] Output: 28 Explanati
LeetCode[421] Maximum XOR of Two Numbers in an Array Given a non-empty array of numbers, a0, a1, a2, … , an-1, where 0 ≤ ai < 231. Find the maximum result of ai XOR aj, where 0 ≤ i, j < n. Could you do this in O(n) runtime? Example: Input: [3, 10, 5, 25,...
Solution 1: Bit Manipulation: 这题真心有点难,get the max XOR bit by bit note that if A^B=C, then A^C=B, B^C=A 1publicclassSolution {2publicintfindMaximumXOR(int[] nums) {3intmask = 0, max = 0;4for(inti=31; i>=0; i--) {5mask |= 1<<i;6HashSet<Integer> prefixes =...
参考这个链接[LeetCode] Maximum XOR of Two Numbers in an Array 数组中异或值最大的两个数字 这个方法肯定想不到 代码如下: #include <iostream> #include <vector> #include <map> #include <unordered_map> #include <set> #include <unordered_set> ...
Python: classSolution:deffindMaximumXOR(self,nums:List[int])->int:l,result=len(bin(max(nums))[2:]),0foriinrange(l)[::-1]:result<<=1cur=result|1d={num>>ifornuminnums}result|=any(cur^jindforjind)returnresult
Flipping a subset of columns is like doing a bitwise XOR of some number K onto each row. We want rows X with X ^ K = all 0s or all 1s. This is the same as X = X^K ^K = (all 0s or all 1s) ^ K, so we want to count rows that have opposite bits set. For example, ...
详解地址:https://www.acwing.com/solution/LeetCode/content/549/ classSolution{ public: classTreeNode { public: TreeNode* next[2]; TreeNode() { next[0] =NULL; next[1] =NULL; } }; intfindMaximumXOR(vector<int>& nums) { TreeNode* root = build(nums); ...
https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/91049/Java-O(n)-solution-using-bit-manipulation-and-HashMap https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/91064/C%2B%2B-22-ms-beats-99.5-array-partitioning-similar-to-quick-sort ...