#include<vector>#include<algorithm>usingnamespacestd;intmaxSubArray(vector<int>& nums){// 如果数组为空,直接返回0if(nums.empty())return0;intmaxSum = nums[0];// 初始化最大子数组和为数组的第一个元素intcurrentSum = nums[0];// 初始化当前最大子数组和为数组的第一个元素// 从数组的第二个...
classSolution{public:intmaxSubArray(vector<int>& nums){intn = nums.size();if(n ==0)return0;intret = nums[0], sum =0, min_sum =0;for(inti =0; i < n; ++i) { sum += nums[i]; ret =max(ret, sum - min_sum); min_sum =min(min_sum, sum); }returnret; } }; 思路3:...
sum is",find_maximum_subarray(A, 0, len(A) - 1), '\n') print('using Kanade Algorithm...') print("Maximum contiguous sum is", maxSubArraySum(A, len(A)), '\n') print('using dynamic programming...') MS = DP_maximum_subarray(A) print("Maximum contiguous sum is", max(MS), ...
53. Maximum Subarray 53. Maximum Subarray 方法1: dynamic programming Complexity 易错点: 方法2: divide and conquer 易错点: 方法1: dynamic programming 思路: 因为是连续位置的数列和,只有两种情况,遍历到nums[i]的时候只能选择取或不取。取的话curSum = curSum + nums[i] ,或者以 i 为起点... 猜...
intarrVal=maxSubArray(temp);maxVal=max(maxVal,arrVal);}}returnmaxVal;} 关于DP,有个博客讲解的非常详实,感兴趣的可以看看,地址:演算法笔记。 References Chapter07-_Submatrix_with_largest_sum Maximum Sum Rectangular Submatrix in Matrix dynamic programming/2D kadane...
本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续...
LeetCode1856.子数组最小乘积的最大值 Maximum Subarray Min-Product(Java) LeetCode1856.子数组最小乘积的最大值 Maximum Subarray Min-Product(Java) ##Binary Search##, ##Dynamic Programming##, ##Sort##, ##Union Find##, ##Queue##, ##Dequeue## 最小乘积定义为这个数组中最小值乘以数组的和,...
the contiguous subarray [4,−1,2,1] has the largest sum = 6. More practice: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle. Hide Tags Divide and Conquer Array Dynamic Programming ...
How to Find Maximum Sum Subarray Given an array of integers, the task is to find the maximum subarray sum possible of all the non-empty arrays. Input: [−2, 1, −3, 4, −1, 2, 1, −5, 4] Output: 6 Explanation: Subarray [4, −1, 2, 1] is the max sum contiguous ...
Explanation: [4,-1,2,1] has the largest sum = 6. 这个题目思路跟[LeetCode] 198. House Robber _Easy tag: Dynamic Programming很像, 我们只需要得到动态方程式, A[i] 是maxsum which contains nums[i] for sure, then A[i] = max(A[i-1] + nums[i], nums[i]), init: A[0] = nums[...