Given an integer arraynums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1] Output: 0 Explanation: The ...
Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array[2,3,-2,4], the contiguous subarray[2,3]has the largest product =6. 题意及分析:给出一个数组,求出乘积最大的子数组。这道题可以使用动态规划的方法求解,...
思路:结合最大子数组和,这里用两个变量分别记下包含当前元素的最大乘积和最小乘积,因为下一个元素正负不定。 Runtime: 2 ms, faster than 74.69% of Java online submissions for Maximum Product Subarray. Memory Usage: 37.6 MB, less than 100.00% of Java online submissions for Maximum Product Subarray....
Output: True Explanation: You could delete the character 'c'. Note: The string will only contain lowercase characters a-z. The maximum length of the string is 50000. 判断回文字符串 双指针 java解决 两头相会 AI检测代码解析 class Solution { public boolean validPalindrome(String s) { for(int i...
the contiguous subarray [2,3] has the largest product = 6. class Solution { public int maxProduct(int[] nums) { int[] max = new int[nums.length]; int[] min = new int[nums.length]; min[0] = max[0] = nums[0]; int result = nums[0]; ...
importjava.util.stream.IntStream; /** * 最大连续子数组的乘积 * * Find the contiguous subarray within an array (containing at least one number) which has the largest product. * * For example, given the array [2,3,-2,4], * the contiguous...
public int maxSubArray(int[] nums) { int max = nums[0]; int sum = nums[0]; for(int i = 1; i < nums.length; i++){ sum = sum < 0 ? nums[i] : sum + nums[i]; max = Math.max(sum, max); } return max; } }
10.3.1 (python) 动态规划数组类LeetCode题目 —— Minimum Path Sum & Triangle & Maximum Product Subarray 这一节的几篇,都是解析动态规划数组类题目,相对于后面的字符串类问题来说,还是比较容易的。 首先来看比较几个简单的DP题目,巩固一下前面所学套路。 64. Minimum Path Sum Given a m x n grid ...
classSolution {publicintmaxSubArray(int[] nums) {intmaxSum = Integer.MIN_VALUE;//注意有负数的时候,不能初始化为0intcurrentSum =Integer.MIN_VALUE;for(inti = 0; i < nums.length; i++){if(currentSum < 0) currentSum =nums[i];elsecurrentSum +=nums[i];if(currentSum > maxSum) maxSum...
Maximum Subarray (JAVA) Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array[−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray[4,−1,2,1]has the largest sum =6....