path maximum querypath maximum sum querytreeLet T be a node-weighted tree with n nodes, and let π(u, v) denote the path between two nodes u and v in T. We address two problems: (i) Path Maximum Query: Preproces
Let T be a node-weighted tree with n nodes, and let π(u, v) denote the path between two nodes u and v in T. We address two problems: (i) Path Maximum Query: Preprocess T so that, for a query pair of nodes u and v, the maximum weight on π(u, v) can be found quickly....
The maximum path sum of a tree is a path from two nodes in the tree, that sums up to the maximal value possible. The path can always be divided into three parts: root, left path, right path. There might be nodes with negative weight, so the left and right paths could be empty whe...
Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example: Given the below binary tree, 1 / \ 2 3 Return6. 思路: 用递归方法从叶节点开始,将所求最大路径和maxValue设为全局变量,并赋初始值。 假设递归到节点n,首先计算左子树的最大...
public int maxPathSum(TreeNode root) { if (root == null) { return Integer.MIN_VALUE; } //左子树的最大值 int left = maxPathSum(root.left); //右子树的最大值 int right = maxPathSum(root.right); //再考虑包含根节点的最大值 int all = ...; return Math.max(Math.max(left, right...
Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path does not need to go through the root. ...
维护一个全局变量maxSum存储最大路径和,在递归过程中更新maxSum的值,最后得到的maxSum的值即为二叉树中的最大路径和。 Code class TreeNode: def __init__(self, x): self.val = x self.left = None self.right = None class Solution: def __init__(self): ...
78 -- 9:48 App LeetCode刷题日记 Day 23 Part 2 - Search in Rotated Sorted Array 154 -- 3:19 App LeetCode刷题日记 Day 40 Part 1 - Matrix Diagonal Sum 89 -- 5:01 App LeetCode刷题日记 Day 6 Part 2 - Binary Tree Level Order Traversal浏览...
LintCode 94. Binary Tree Maximum Path Sum Description Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. Example Given the below binary tree: 1 / \ 2 3 return 6. 解题 题意是找到整棵树中,值最大的一条路径。
http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。 ** 总结: pre-order -> top-down post-order -> bottom-up in-order -> ? level-order -> bfs ...