Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1. Example 2: Input: [1, 2] Out...
def maxNumber(nums1, nums2, k): # 准备函数:从给定数组中选择k个最大的数,保持原有顺序。 def prepare(nums, k): drop = len(nums) - k # 计算需要丢弃的元素数量 stack = [] # 使用栈来存储选定的元素 for num in nums: # 如果栈不为空,并且当前元素大于栈顶元素,且还需要丢弃元素时,弹出栈...
Given two arrays of lengthmandnwith digits0-9representing two numbers. Create the maximum number of lengthk <= m + nfrom digits of the two. The relative order of the digits from the same array must be preserved. Return an array of thekdigits. You should try to optimize your time and ...
1798. 你能构造出连续值的最大数目 - 给你一个长度为 n 的整数数组 coins ,它代表你拥有的 n 个硬币。第 i 个硬币的值为 coins[i] 。如果你从这些硬币中选出一部分硬币,它们的和为 x ,那么称,你可以 构造 出 x 。 请返回从 0 开始(包括 0 ),你最多能 构造 出多少个
参考这个链接[LeetCode] Maximum XOR of Two Numbers in an Array 数组中异或值最大的两个数字 这个方法肯定想不到 代码如下: #include <iostream> #include <vector> #include <map> #include <unordered_map> #include <set> #include <unordered_set> ...
13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 参考文献 [LeetCode] Maximum XOR of Two Numbers in an Array 数组中异或值最大的两个数字【特别好】【位运算】maximum-xor-of-two-numbers-in-an-array
LeetCode 152. Maximum Product Subarray 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode 1 人赞同了该文章 Description Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1...
Can you solve this real interview question? Number of Subarrays with Bounded Maximum - Given an integer array nums and two integers left and right, return the number of contiguous non-empty subarrays such that the value of the maximum array element in th
1953. 你可以工作的最大周数我一周都不想工作 你
Given integer array nums, return the third maximum number in this array. If the third maximum does not exist, return the maximum number. Example 1: Input: nums = [3,2,1] Output: 1 Explanation: The third maximum is 1. Example 2: ...