The x-coordinate of the vertex can be found using the formula:x=−b2awhere a=−1 and b=6:x=−62×−1=3 Step 5: Calculate the maximum heightNow, we substitute x=3 back into the original equation to find the maximum height:y=−32+6⋅3−5Calculating this gives:y=−9+...
The ball reaches a maximum height of 140 feet. c. To find when the ball hits the ground, we need to determine when the height is zero, H(t)=0.H(t)=0. We use the quadratic formula. ⎧⎪⎪⎨⎪⎪⎩t=−80±√802−4(−16)(40)2(−...
After using the quadratic formula I got x2=48.02. I added that max stretch to 44.1 and got 92.12m, which is way more than 52 (the height of the platform). So my answer is that yes the box will hit the ground. But I’m not really sure that I did this right ...
Answer to: A ball is thrown directly upward. Its height h (in feet) after t seconds is given by h(t) = 5 + 80t - 16t2. Find the maximum height the...
Robbie observed that a golf ball followed a parabolic path for which the height is approximated by the quadratic function h(t) = -4t2 + 14.4 t, where h(t) is the height in metres and t is the time in seconds. a) Find the time the golf ball reaches its maximum height and the max...
Twenty-five healthy and physically active males participated in the study (age: 22.9 ± 2.2 years, height: 1.8 ± 0.07 m, weight: 76.9 ± 8.2 kg). The subjects performed a minimum of 6 months of weekly resistance training involving lower body, and a minimum of 2 years of experience with...
Therefore, for a quadratic form in the exponential function of Equation (36), we change the expression of Equation (36) to ∫ 0 t 1 e − ( a + α ) t − ( b t 2 / 2 ) d t = 2 b e ( a + α ) 2 / 2 b ∫ ( a + α ) / 2 b ( b / 2 ) ( t 1...
From the elementary theory of quadratic forms, known since long time, follows that the rank of a quadratic form f ∈ S 2 , equals the rank of its representing matrix with respect to whatever given (ordered) basis. Hence, the maximum rank equals dim S 1 , that is, the number of indete...
By the property of quadratic function, we have Q i ≤ η t G ( f t , D ( x i ) − y i ) 2 2 σ 2 2 y i 2 − − G ( f t , D ( x i ) − y i ) 2 2 σ 2 + η t G ( f t , D ( x i ) − y i ) 2 2 σ 2 2 y i 2 η t G ( f...
For example, if the parabolic case (where the energy is a quadratic function of the wave vector) is considered, the same drawbacks of classical gas-dynamics arise regarding the lack of integrability of the MEP distribution function. In the case of the Kane dispersion relation, the solvability ...