r=r+self.maxDepth(root.right) ifl>r: returnl else: returnr 1、在开始的时候经常遇到“NoneType”Error,后来查阅资料才知道使用 root==None 就可以处理这种情况; 2、调用函数的时候不需要传递self值,这个应该是Python自己传递的,如果自己添加上,反而会报错; 3、这道题目说明不是很清晰,系统的输入是{},{0...
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求二叉树的深度,递归一下就可以求到了。 python新手(我)发现python中没有三元运算符,不过可以用true_part if condition else false_part...
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 1. 2. 3. # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x...
在Python中实现二叉树的最大路径和有哪些关键点? 题目大意 求一棵二叉树中最大的路径和。该路径可以是二叉树中某一节点到树中任意一个节点的所经过的路径,不允许重复经过一个节点,不必经过根节点。 解题思路 参考: https://shenjie1993.gitbooks.io/leetcode-python/124%20Binary%20Tree%20Maximum%20Path%20...
python递归深度报错--RuntimeError: maximum recursion depth exceeded 2018-02-13 11:32 −... bingo彬哥 0 1081 [Leetcode] 104. Maximum Depth of Binary Tree 2019-12-08 11:38 −1 int depth = 0; 2 int currentMaxDepth = 0; 3 public int maxDepth(TreeNode root) { 4 if(root == nul...
求一棵二叉树中最大的路径和。该路径可以是二叉树中某一节点到树中任意一个节点的所经过的路径,不允许重复经过一个节点,不必经过根节点。 解题思路 参考: https://shenjie1993.gitbooks.io/leetcode-python/124%20Binary%20Tree%20Maximum%20Path%20Sum.html ...
题目描述: {代码...} connections. The path must contain at least one node and does not needto go through the root. 举例: {代码...}
0110-balanced-binary-tree.cpp 0111-minimum-depth-of-binary-tree.cpp 0115-distinct-subsequences.cpp 0116-populating-next-right-pointers-in-each-node.cpp 0117-populating-next-right-pointers-in-each-node-ii.cpp 0118-pascals-triangle.cpp 0120-triangle.cpp 0121-best-time-to-buy-and-sell-stock.cpp ...
0111-minimum-depth-of-binary-tree.cpp 0115-distinct-subsequences.cpp 0116-populating-next-right-pointers-in-each-node.cpp 0117-populating-next-right-pointers-in-each-node-ii.cpp 0118-pascals-triangle.cpp 0120-triangle.cpp 0121-best-time-to-buy-and-sell-stock.cpp 0122-best-time-to-buy-and-se...
代码(Python3) class Solution: def maximumSubarraySum(self, nums: List[int], k: int) -> int: # ans 维护所有长度为 k 且数字各不相同的子数组中,子数组和的最大值 ans: int = 0 # sum 维护当前滑动窗口 [l, r] 内的数字和 sum: int = 0 # num_to_cnt 表示滑动窗口 [l, r] 内每个数...