原题链接在这里:https://leetcode.com/problems/maximum-sum-bst-in-binary-tree/description/ 题目: Given a binary treeroot, returnthe maximum sum of all keys of any sub-tree which is also a Binary Search Tree (BST). Assume a BST is defined as follows: The left subtree of a node contains...
Can you solve this real interview question? Maximum Sum BST in Binary Tree - Given a binary tree root, return the maximum sum of all keys of any sub-tree which is also a Binary Search Tree (BST). Assume a BST is defined as follows: * The left subtree
TreeNode* constructMaximumBinaryTree(vector<int>&nums) {if(nums.empty())returnNULL;returnhelper(nums,0, nums.size() -1); } TreeNode* helper(vector<int>& nums,intleft,intright) {if(left > right)returnNULL;intmid =left;for(inti = left +1; i <= right; ++i) {if(nums[i] >nums[...
Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number. The right subtree is the maximum tree ...
So how can we find kth maximum given the binary search tree and the k as input? The idea isreverse inorder traversal. If we do the reverse inorder traversal then we will reach to the maximum node in the BST first. So, we need to keep a counter which will increment to find the kth...
TreeNode*root=newTreeNode(16); root->left=newTreeNode(3); root->left->right=newTreeNode(13); root->left->right->left=newTreeNode(10); root->right=newTreeNode(20); root->right->left=newTreeNode(18); cout<<"Minimum value in the BST is: "<<minValue(root)<<endl; ...
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Binary tree is a special kind of tree where each node has a maximum of two children. The topmost node in the tree is called 'root' node. The left reference of the root node is called the 'left child' while the right reference is called the 'right child' of the ro...
Binary Tree Maximum Node Find the maximum node in a binary tree, return the node. Example Given a binary tree: 1 / \ -5 2 / \ / \ 0 3 -4 -5 return the node with value3. 1publicclassSolution {2/**3*@paramroot the root of binary tree4*@returnthe max ndoe5*/6publicTreeNode...