题目来源:https://leetcode.com/problems/maximum-binary-tree/description/ Description Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left pa...
classTreeNode{intval; TreeNode left; TreeNode right; TreeNode(intx) { val = x; } }publicclassSolution{publicstaticTreeNodeconstructMaximumBinaryTree(int[] nums){if(nums.length==0)returnnull;intmax=getMaxNumber(nums); TreeNode root=newTreeNode(max); root.left=constructMaximumBinaryTree(getAr...
https://leetcode.com/problems/maximum-binary-tree/ https://leetcode.com/problems/maximum-binary-tree/discuss/106146/C%2B%2B-O(N)-solution https://leetcode.com/problems/maximum-binary-tree/discuss/106194/javac-simple-recursive-method https://leetcode.com/problems/maximum-binary-tree/discuss/106...
# Definition for a binary tree node.# class TreeNode:# def __init__(self, x):# self.val = x# self.left = None# self.right = NoneclassSolution:defconstructMaximumBinaryTree(self, nums:List[int]) -> TreeNode:# 特判ifnotnums:returnNone# 找到数组中的最大值和对应的索引maxVal =max(n...
Leetcode之分治法专题-654. 最大二叉树(Maximum Binary Tree) 给定一个不含重复元素的整数数组。一个以此数组构建的最大二叉树定义如下: 二叉树的根是数组中的最大元素。 左子树是通过数组中最大值左边部分构造出的最大二叉树。 右子树是通过数组中最大值右边部分构造出的最大二叉树。
publicclassSolution { publicTreeNode constructMaximumBinaryTree(int[] nums) { if(nums ==null)returnnull; returnbuild(nums,0, nums.length -1); } privateTreeNode build(int[] nums,intstart,intend) { if(start > end)returnnull; intidxMax = start; ...
Given anon-empty binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must containat least one node and does not need to go through the root. ...
https://leetcode.com/problems/binary-tree-maximum-path-sum/discuss/39775/Accepted-short-solution-in-Java https://leetcode.com/problems/binary-tree-maximum-path-sum/discuss/39869/Simple-O(n)-algorithm-with-one-traversal-through-the-tree
* TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public:TreeNode*insertIntoMaxTree(TreeNode* root,intval){if(root ==NULL){returnnewTreeNode(val); }else{if(root->val < val){ ...
* };*/classSolution {public:intmaxDepth(TreeNode *root) {if(root ==NULL)return0;elsereturnmax(maxDepth(root->left), maxDepth(root->right)) +1; } }; 解法二:深度优先遍历,栈的最大容量即最大深度 /** * Definition for binary tree ...