The term for the y-coordinate of the vertex of a parabola that opens down The term for the y-coordinate of the vertex of a parabola that opens up Calculating the minimum or maximum value of a parabola Skills
To see whether it is a maximum or a minimum, in this case we can simply look at the graph.f(x) is a parabola, and we can see that the turning point is a minimum. By finding the value of x where the derivative is 0, then, we have discovered that the vertex of the parabola is...
If you are given the graph of a quadratic function or able to graph it with a calculator, then it is simple to find the maximum or minimum value. Look for the vertex of the parabola and draw a horizontal line to the y-axis to find what the minimum or maximum value is.View...
Function at a given interval f(x) = x^3, x in [-2,2] Find the absolute maximum value and the absolute minimum value of. View Solution Find the absolute maximum value and the absolute minimum value of the functions in the given intervals: f(x) =x3,x∈[– 2, 2] View Solution ...
A quadratic function contains the square of the variable. The vertex formula for a quadratic equation will be f(x)=a(x−h)2+k where (h,k) are the coordinates of the vertex, that is, the minimum or maximum of the parabola.Answer and Explana...
First, determine whether this parabola opens upward, and has a minimum, or opens downward, and has a maximum. Since the first term is negative, this opens downward, so you're finding a maximum. Next, figure out where the vertex is. The axis of symmetry is -b/2a, when you consider th...
The second order derivative is used to find the maxima or minima point. Answer and Explanation: The given equation is of the parabola. So this curve can have either the maximum or minimum value but not the both at a time. We will first find...
Example 10: Applying the Vertex andx-Intercepts of a Parabola A ball is thrown upward from the top of a 40 foot high building at a speed of 80 feet per second. The ball’s height above ground can be modeled by the equationH(t)=−16t2+80t+40.H(t)=...
Consider 2 ) 1 x x + . This is an upward opening parabola with a vertex at (0,1). The smallest function value this function takes on is 1.We say thatf has an absolute minimum of 1 at x=0.Note thatf does not have an absolute maximum value. If you find a function value, I ...
Find the absolute maximum value and minimum value of the function. f(x)=12x^(4/3)-6x^(1/3), x in [-1,1]