maximumSizeSubarraySumEqualsK.java │ ├── minimumWindowSubstring.java │ ├── sparseMatrixMultiplication.java │ ├── strobogrammaticNumber.java │ ├── twoSum.java │ └── uniqueWordAbbreviation.java ├── LinkedList │ ├── addTwoNumbers.java │ ├── deleteNodeInALinkedList....
so that its total length is e(i) - b(i) + 1. Also let's define a function next(i) that returns the position within the tuple list of the first tuple that can appear to the right-hand side of tuple i. Notice that next(i) can be calculated in O(log n) time with a binary ...
// find the minimum and the maximum elements in subarray `arr[i…j]` intmin=*min_element(arr+i,arr+j+1); intmax=*max_element(arr+i,arr+j+1); // if subarray `arr[i…j]` is not balanced, choose the minimum // removals among subarray `arr[i…j-1]` and `arr[i-1…j]` ...