divide&conquer:find max array package max_subarrayy; import java.lang.Math; public class max_subarrayy { private static int[] array; public static class mark{ private int lom = 100; private int him; private int value; public mark(int a,int b,int c){ lom = a;him = b;value = c;...
Mergesort is also a divide and conquer algorithm. It continuously divides an array into two halves, recurses on both the left subarray and right subarray and then merges the two sorted halves Stable: Yes Time Complexity: Best Case: O(nlog(n)) Worst Case: O(nlog(n)) Average Case: O(...
// find the minimum and the maximum elements in subarray `arr[i…j]` intmin=*min_element(arr+i,arr+j+1); intmax=*max_element(arr+i,arr+j+1); // if subarray `arr[i…j]` is not balanced, choose the minimum // removals among subarray `arr[i…j-1]` and `arr[i-1…j]` ...
O(n2) time complexity and O(1) space complexity squareSum.cpp Given an unsorted array arr[0..n-1] of size n, find the minimum length subarray arr[s..e] such that sorting this subarray makes the whole array sorted. minLengthUnsortedArray.cpp Find the missing number in Arithmetic ...