必应词典为您提供max-eigenvalue的释义,网络释义: 最大特征值;最大单位根;
The eigenvalue problem for an irreducible non negative matrix $A=[a_{ij}]$ in the max-algebra is the form $A \\otimes x = \\lambda x$ where $(A \\otimes x)_i = \\max (a_{ij}x_j), x=(x_1,x_2, \\dots, x_n)^t $ and $\\lambda $ refers to maximum cycle ...
...后阶数,而后采 取迹检验(Trace Test)或最大特征值检验(Max-Eigenvalue Test),检验变 量之间是否存在协整关系。www.docin.com|基于3个网页 2. 检验结果 表4b 协整关系检验结果(Max-eigenvalue test)注:*(**)表示在5%(1%)的显著水平上拒绝原假设 由表4可知期货价格旬度指数时间序 …www.lunwen588.com...
Yeah, I know there are many functions for Fortran 95 to compute the eigenvalue of real matrix. But in my test, the syevd is the most fast function than other functions, such as the sygvx, which can select eigenvalues. So I want to konw which function is the most...
Max-min eigenvalue problems, primal-dual interior point algorithms, and trust region subproblems - RENDL, VANDERBEI, et al. - 1993 () Citation Context ...nite constraints. This is partly due to new applications to integer programming and min-max eigenvalue problems as well as to successful ...
因此,得到符合一致性检验的最大特征值λ_max的范围,如公式(10)。 35/5000 源语言: 自动识别 目标语言: 英语 结果(英语) 1: [复制] Therefore, the range of the maximum eigenvalue λ_max that meets the consistency test is obtained, as in formula (10). 结果(英语) 2:[复制] Therefore, the ...
In this contribution an optimization procedure that maximizes the minimum of the eigenvalue damping ratios of linear systems in prescribed frequency ranges is discussed. The method is based on reformulating a given design task as a problem to obtain a structured, static output feedback controller. ...
Eigenvalue Processor Parameters Transient Response Processor Parameters Frequency Response Processor Parameters Nonlinear Solution Processor Parameters ADDNLTOQUADLOAD ADPCON AUTOFIXNLMAT BARDKMETHOD BISECT COMPE1RSF COMPE1RSFTID COMPE2RSF COMPE2RSFTID COMPE3RSF COMPE3RSFTID COMPG12RSF COMPG12RSFTID CO...
Combining this max-plus basis with the max-plus linearity of the semi-group leads to a reduction of the problem to that of finding a max-plus eigenvector corresponding to eigenvalue 0, that is, the nonlinear problem reduces to a max-plus linear problem...
Proof: From part (2) above, the smallest eigenvalue of M is given by Noting that we always have , then if and only if the numerator on the right is always non-negative. Lemma 3 If , then Proof: , . By Lemma 2, this implies . Lemma 4 If and , then Proof: , . By ...