=》 相似 对角阵 AB, BA: 相同的 特征值 how? 证明: AB, BA 相似 =》其 特征值 相同,特征向量 maybe 不同 if 特征值为0 =》无法得到 可逆矩阵 =》 无法 使用相似 不同矩阵 —— 特征值 不可直接 运算:加、减、乘、除 特征值(A) * 特征值(B)!= 特征值(AB) 特征值(A) + 特征值(B)!= ...
百度试题 结果1 题目Find AB and BA, if possible.A=(bmatrix) -1&3 -3&2(bmatrix), B=(bmatrix) -2&4&0 -3&-1&2(bmatrix) 相关知识点: 试题来源: 解析 AB=(bmatrix) -7&-7&6 0&-14&4(bmatrix) ; BA is undetined.反馈 收藏 ...
If A is any mxxn matrix such that AB and BA are both defined, then B is a matrix of order
AB is undefined; BA=(bmatrix) -14&20&4 10&-12&3(bmatrix) 张岱在《湖心亭看雪》中用比喻手法描绘雪后西湖的句子是:“雾凇沉砀,天与云与山与水,上下一白,湖上影子,惟长堤一痕、湖心亭一点、与余舟一芥、舟中人两三粒而已”。这句话将雪后西湖比作一幅画,通过“一痕”、“一点”、“一...
要注意的是：可置换性不一定成立，即有矩阵 A 及 B 使得 AB ≠ BA。对其他特殊乘法，见矩阵乘法。其他性质 [编辑本段]线性变换，秩，转置 矩阵是线性变换的便利表达法，皆因矩阵乘法与及线性变换的合成有以下的连系：以 Rn 表示 n×1 矩阵（即长度为n的矢量）。对每个线性变换 f : Rn -> ...
- Matrix B has m rows and 11−n columns. 2. Determine the conditions for the existence of the matrix products AB and BA: - For the product AB to exist, the number of columns in A must equal the number of rows in B. Therefore: n+5=m(Equation 1) - For the product BA to exis...
南航双语矩阵论matrix theory第3章部分习题参考答案
The matrixChas as many rows asAand as many columns asB. Unlike the multiplication of ordinary numbersaandb, in whichabalways equalsba, the multiplication of matricesAandBis not commutative. It is, however, associative and distributive over addition. That is, when the operations are possible, the...
If A and B are invertible matrices, then AB is also invertible. Thus, (AB)^-1 = B^-1A^-1 If A is nonsingular then (A^T)^-1 = (A^-1)^T The product of a matrix and its inverse and vice versa is always equal to the identity matrix....
Given two square matrices A, B of the same size, the two matrices AB and BA may have different ranks. A non-zero square matrix A is called a rank-commutator of a family L of n x n matrices if rank(AL) = rank(LA) holds for every L in L. In this paper, we investigate the ...