Note that, for example, the primal (objective) can be unbounded and the primal residual, which ...
// Initialize function 'Perform' input arguments. // Initialize function input argument 'data'. data = argInit_UnboundedxUnbounded_real_T(); // Initialize function input argument 'data1'. data1 = argInit_1xUnbounded_cell_wrap_0(); // Call the entry-point 'Perform'. Perform(data, data1...
max f (x1, x2)=x1x2+3 sub.to x1+x2-2=0 解：化成标准形式：sub.to x1+x2=2 在Matlab中实现如下：>>H=[0,-1;-1,0];>>f=[0;0];>>Aeq=[1 1];>>b=2;>>[x,fval,exitflag,output,lambda] = quadprog(H,f,[ ],[ ],Aeq,b)结果为：x = 1.0000 1.0000...
% if no bounds exist. Set LB(i) = -Inf if X(i) is unbounded below; % set UB(i) = Inf if X(i) is unbounded above. % % X = FMINCON(FUN,X0,A,B,Aeq,Beq,LB,UB,NONLCON) subjects the minimization % to the constraints defined in NONLCON. The function NONLCON accepts X % and ...
Problem appears unbounded. fmincon stopped because the objective function value is less than the value of the objective function limit and constraints are satisfied to within the value of the constraint tolerance. sb =2×1 1.0e+20 * 3.2933 -0.0000 ...
If x(i) is unbounded below, set lb(i) = -Inf, and if x(i) is unbounded above, set ub(i) = Inf. Note If the specified input bounds for a problem are inconsistent, fmincon throws an error. In this case, output x is x0 and fval is []. For the default 'interior-point' ...
41. FUNCTION PRECISION >0 3.0E-13 eps0.8=epsR 42. DIFFERENCE INTERVAL >0 5.48E-7 eps0.4 43. CENTRAL DIFFERENCE INTERVAL >0 6.69E-5 eps0.8/3 44. COMPLETION 0 1 LC, 0 NC 1 0=PARTIAL 1=FULL 45. UNBOUNDED STEP SIZE >0 1E10 46. UNBOUNDED OBJECTIVE >0 1E20 Hessian approximation 47...
Problem is unbounded. ans = [] So if I ignore the bound constraints, it looks like there might conceivably be solutions. (Actually, I think there will not be any anyway, but that seems irrelevant to chase down.) But when I add in the bound constraints, things get more...
how can i solved it and the proble is (Exiting: the problem is unbounded.) the code is %To minimize our fitness function using the linear programming function, we need to pass in a function handle to the fitness function as well as specifying the number of variables as the second argument...
;调用函数 linprog 解上述问题:x,fval,exitflag,output,lambda= linprog(f,A,b,Aeq,beq,lb)Exiting: One or more of the residuals, duality gap, or total relative error has grown 100000 times greater than its minimum value so far: the primal appears to be infeasible (and the dual unbounded)....