The function takes two arguments: the equations to solve and the variables to solve for. For example, if you have a single-variable equation like "x^2 - 5x + 6 = 0," you can use Matlab Solve as follows: ```matlab syms x eq = x^2 - 5*x + 6 == 0; sol = solve(eq, x)...
Solve Equation Finally, solve the equation using the symmetry m, the PDE equation, the initial conditions, the boundary conditions, and the meshes for x and t. Get m = 0; sol = pdepe(m,@pdex1pde,@pdex1ic,@pdex1bc,x,t); pdepe returns the solution in a 3-D array sol, where ...
b];RA=rank(A)RB=rank(B)Y=null(A,'r')n=length(b)ifRA==RBifRA==nX=A\B%方程组满秩时,求出唯一解elsep=pinv(A)*b%在方程组不满秩时,求出特解Y=null(A,'r')%求出方程组的基础解系n1=length(Y(1,:))k=sym(['kI'])%这里是ki,是为了把数组k说明成字符型变量fori=1:n1%求...
These are my formula and alpha and L2 are my variable. I want to calculate the value of L2 for alpha from 0 to 42 in steps of 1. But when I solve the equation, I still get the answer in terms of L2 and not a numerical value. ...
function [X,FVAL,EXITFLAG,OUTPUT,LAMBDA,GRAD,HESSIAN] = fmincon(FUN,X,A,B,Aeq,Beq,LB,UB,NONLCON,options,varargin) /*fmincon可以在多元函数中找到最小值 FMINCON attempts to solve problems of the form: min F(X) subject to: A*X <= B, Aeq*X = Beq (linear constraints)线性约束 X C(X...
Functions to solve, specified as a function handle that defines the functions to be integrated. The function f = odefun(t,y,yp), for a scalar t and column vectors y and yp, must return a column vector f of data type single or double that corresponds to f(t,y,y′). odefun must ...
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odefun—Functions to solve function handle Functions to solve, specified as a function handle that defines the functions to be integrated. The functiondydt = odefun(t,y), for a scalartand a column vectory, must return a column vectordydtof data typesingleordoublethat corresponds tof(t,y)....
Solve the following neutral DDE, presented by Paul, for. The solution history is for . Create a new program file in the editor. This file will contain a main function and four local functions. Define the first-order DDE as a local function namedddefun. ...
Trying to solve an integration with several functions, each of which is dependent upon a single variableCForcef(x) returns a vector if x is a vector. (h/2-x) returns a vector if x is a vector. You ask for matrix multiplication, "*" between the ...