I display dims on all signals, so no display means scalar. This doesn't work: SL is confused on dims for some reason. Error: Why? Isn't a matrix multiply output just a number, if the dimensions end up as 1x1? What am I misunderstanding?
把y的表达式改成下面就可以了 y=sqrt((442.1.*cos(x+4)-12.4).^2+(442.1.*sin(x+4)-174.9).^2);错误出现的原因，矩阵元素的幂，不等于矩阵的幂，矩阵的幂是 ^ 而矩阵元素的幂就是 .^ 请注意区别
这段程序把第一行表达式左侧的两个X变成小写，就可以正常运行。[x1,x2]=meshgrid(0:0.001:0.005,0:0.001:0.006);Z=0.7572+sqrt(0.022+(40.55*x1).^2+(42.53*x2).^2);mesh(X1,X2,Z);xlabel('自变量x1'),ylabel('自变量x2'),zlabel('函数值f(x1,x2)');结果为：
就你认为错误的那句是正确的。由于y=--2:0.01:2;多了一个负号，导致[x,y]=meshgrid(x,y);得到的结果不是二维数组而是行向量，所以f算出也是向量，导致mesh根本不能用。去掉那个多余负号即可。
把y的表达式改成下面就可以了 y=sqrt((442.1.*cos(x+4)-12.4).^2+(442.1.*sin(x+4)-174.9).^2);错误出现的原因，矩阵元素的幂，不等于矩阵的幂，矩阵的幂是 ^ 而矩阵元素的幂就是 .^ 请注意区别
Matrix dimensions must agree. 或者 Error using * Integers can only be combined with integers of the same class, or scalar doubles. 原因: 如果参与矩阵乘法的矩阵包含不同的数据类型(如整数和浮点数),这可能导致错误。 解决方案: 确保所有参与矩阵乘法的矩阵都是相同的数据类型,如果一个是整数,另一个是浮...
我猜你的代码应该是 surf(Xp(i),Yp(i),Zp(i)) 出错了吧，当x和y为1*10的向量时，则构成了一个10*10的二维平面，因此此时z应该是一个10*10的矩阵，而不是标量或矢量，错误提示：Z must be a matrix, not a scalar or vector 就是这个意思。
Fast Matrix Multiply with Multi-Dimensional Support MTIMESXis a fast general purpose matrix and scalar multiply routine that has the following features: Supports multi-dimensional (nD, n>2) arrays directly Supports Transpose, Conjugate Transpose, and Conjugate pre-operations ...
z必须是二维的，而不是一个向量数组
In this formula, Ry is a matrix for rotation about the y-axis, and Tw is a translation to some position in world coordinates.The order in which you multiply the matrices is important because, unlike multiplying two scalar values, matrix multiplication is not commutative. Multiplying ...