I have a matix where each value is a string and I want to export it to a csv file. I have tried using csvwrite but it doesn't like that my matrix is full of strings, how can I do this? I have also tried using writetable but have encountered the same issue. ...
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Matlab的矩阵需要变量来代替，输入方法为[]内每一行的数字由空格隔开，行与行之间由分号隔开，例如A=[1 2 3 ;4 5 6;7 8 9]，这样显示出来就是三行三列的矩阵。矩阵间的加，乘，除都是用变量和符号来代替的。2.3 Matlab Matrix Operations Matlab's matrix requires variables to replace it. The input ...
Given a matrix, swap the 2nd & 3rd columns If a = [1 2 3 4; 1 2 3 4; 1 2 3 4; 1 2 3 4];then the result is ans = 1 3 2 4 1 3 2 4 1 3 2 4 1 3 2 4Perform a simple swap of the two middle columns. %%x = [1 2 3 4;1 2 3 4;1 2 3 4;1... ...
the rows from A that are not in B. The rows of the matrix C will be in sorted order. [C,IA] = setdiff(A,B) also returns an index vector IA such that C = A(IA). If there are repeated values in A that are not in B, then the index of the last occurrence of each ...
charcols(ndigcols) =false;% Create and fill composite matrix, comp.comp =zeros(num_str,max_len +2*n); comp(:,charcols) = double(s1); comp(:,numcols) = num_val(:,activecols); comp(:,ndigcols) = num_dig(:,activecols);% Sort rows of composite matrix and use index to sort ...
所以在具体的程序中,我们建立一个1×1的实double矩阵(使用 mxCreateDoubleMatrix函数,其返回指向刚建立的mxArray的指针),然后令plhs[0]指向它。接着令指针a指向plhs [0]所指向的mxArray的第一个元素(使用mxGetPr函数,返回指向mxArray的首元素的指针)。同样地,我们把prhs[0]和prhs [1]所指向的元素(即1.1和...
Now, the problem I'm running into in Debug mode is that the strcat(strings) function is outputting a string that is correct, but it's not calling on the previously established variable or matrix. What can I do to make that work?
A=1*6 cell array, A{2}=eye(3) means to generate a 3x3 identity matrix in the 1st row and 2nd column of matrix A. A{5}=magic(5) means to generate a 5x5 magic square matrix, where the sum of the numbers in any row, column, or diagonal is the same. ...
magic(n) generates a magic square of order n, which is to arrange 1-n^2 into an nxnmatrix, so that the sum of n numbers on each row, each column, and the main and sub diagonals of the matrix are equal (It is easy to prove that this sum is equal to n*(n^2+1)/2). B=A...