x=fsolve(eq,1.2345,options); r=1-x 问题描述: No solution found. fsolve stopped because the relative size of the current step is less than the default value of the step size tolerance squared, but the vector of function values is not near zero as measured by the default value of the fu...
运行后发现报错信息为如下: No solution found. fsolve stopped because the problem appears regular as measured by the gradient, but the vector of function values is not near zero as measured by the value of the function tolerance. <stopping criteria details> ans = 1.0140e-08 请问,该如何修改程序...
因此,要深入了解为何会提示“No solution found”,首先应从以上几个方面入手进行检查与修正。 贴吧包打听 1L喂熊 1 回复2楼楼中楼吧友 @LV_双东 :对于非线性方程组的求解,使用fsolve函数和Jacobian函数是常见的做法。然而,有时候在包含Jacobian函数的情况下,求解可能会出现问题。这可能是由于以下几个原因:1. ...
用fsolve解一个四元的齐次非线性方程组,我方程组是用函数写的,在fsolve里调用函数,但是最后的结果总是0 iteration。提示no solution found。每次一运行就秒出结果,一次也不迭代,直接输出初值。尝试过修改初值,限制各种fsolve的条件,也都是一次不迭代,直接显示no solution found 最后输出初值。有有经验的吧u能给个建...
P/S: the general curves of alpha and beta look actually quite right (I'm not sure about the quantity) except the fact that there is a small peak at element 570. I would expect a smooth curve there so I think it's because of the no solution found from fsolve. ...
[ere,fval] = fsolve(@eqn,[4.5;7.5],options); solutionnot found fsolvestopped because the last step was ineffective. However, thevector of function valuesis not near zero, asmeasured by the value of the function tolerance. <stopping criteriadetails> ...
fsolve gives me "no solution found"... Learn more about fsolve, fsolve error, 'no solution found'
I am using 'fsolve' to solve a system of nonlinear equations. However, I recieve this error (No solution found. fsolve stopped because the problem appears to be locally singular.) with every set of initial guess. How can I solve this problem? I provide the an...
x0 = [0.01 0.4 0.2]';这句话后面有个撇号 去掉试试 我也是新手 呵呵 ...
求解方程组的运行结果找不到解的主要问题有：1、用fsolve函数求解的初值问题，解决的方法是通过调整获得。2、求和的问题，在调用myfun(x)时，始终在原地求解当i等于某值时的y值，而没有累加求和。按上述方法，修改后运行可求解得到 x1=-0.78894，x2=0.1253，f1=1.7053e-13，f2=1.6342e-13 ...