Create a new matrix with the for loop팔로우 조회 수: 1 (최근 30일) 이전 댓글 표시 Sophia 2018년 6월 19일 추천 0 링크 번역 답변: Dennis 2018년 6월 20일 채택
forj=1:400; a= round(atan2(h-i,-(k-j))*180/pi); b(i,j)=[a]; end end how can I get (i,j) values for 0<= a <=5 because I want use those indexes to read elements from a "data(i,j)" matrix. Moreover, I want to get (i,j) for several ranges, say 5<= a <=...
Registration Now Open for MathWorks AUTOMOTIVE CONFERENCE 2025 Hello Community, We're excited to announce that registration is now open for the... See Also MATLAB Answers using for loop with syms 1 Answer Can you create a matrix using a for loop 2 Answers Error in port widths or ...
; disp(Loop_x) % 生成N*N的循环矩阵的函数 function C = createLoopMatrix(N) C = zeros(N); for i = 1:N for j = 1:N C(i, j) = mod( i - j, N ); end end end 2.2圆周移位形式的循环矩阵代码对应的效果 2.3对称形式的Toeplitz矩阵 神奇是,仅将上面的代码修改一个地方,就会得到...
I have a 442x25 matrix 'yield' which I want to sum each column in 'yield' to create a 1x25 matrix 'nyi', so this can be multiplied by another 1x25 matrix Np. I ran this exact code earlier on a different computer where both of the matrices were produced the...
Learn how to create a matrix that has an underlying pattern in a for loop, as well as how to use preallocation for the same process.
Your x and y values that come out will be vectors that are scattered around, not a regular grid. You can only use mesh() when the x and y represent grids. If you want a gridded surface then you should look at triscatteredinterp() or the newer griddedinterpolant()In...
% Evaluate Jacobian, calculate eigen values, and store in a preallocated matrix % Assuming the Jacobian will have 3 eigen values, for example eigVals = zeros(3,numel(x)); fork = 1:numel(x)% Don't use i or j for variables J = createJacobian(x(k),y(k),z(k));% You'll ...
So I'm trying to figure out a way to create a matrix of x by y. Say x =[1 2 3 ] and y = [5 6 7 9 10 11]. I'm trying to get my script to shift the longest array y,to the right according to the length of x. So my matrix would look like this:編集済み:Azzi Abd...
Create a 3-by-3 matrix. Index the first row. A = magic(3) A =3×38 1 6 3 5 7 4 9 2 A(1,:) ans =1×38 1 6 Index the second and third column. A(:,2:3) ans =3×21 6 5 7 9 2 Reshape the matrix into a column vector. ...