(Math.abs(s) < 0.001) s=1; // prevent divide by zero, should not happen if matrix is orthogonal and should be // caught by singularity test above, but I've left it in just in case angle = Math.acos(( m[0][0] + m[1][1] + m[2][2] - 1)/2); x = (m[2][1] -...
ABS(X) , Gives the absolute value of X. CEIL(X) , Gives the smallest integer greater than or equal to X. FLOOR(X) , Gives the greatest integer less than or equal to X. ROUND(X) , Rounds X to the nearest integer. RANDOM() , Gets a random value between 0 and 1. MAX(...
absQ2 = det( matrix )^(1/3) quaternion.w = sqrt( max( 0, absQ2 + m00 + m11 + m22 ) ) / 2; ...etc Rounding Errors When comparing different methods of doing this conversion I think we should consider sensitivity to rounding errors. In other words, the matrix contains redundant inf...
在?为什么没有一眼秒? View CodeC: 给定整数a,b,求一非负数k,使得lcm(a+k,b+k)最小。gcd(a+k,b+k)==gcd(a+k,abs(a-b)),它还有个名字叫更相减损术(想起来了吧)。令delta=abs(a-b),枚举delta的所有因子并反推k。 为什么要这样做?题目让lcm最小,那么就是要求最大的gcd ...