最后,第十五、十六行调用Math类中的sqrt方法,求出4的平方根,并输出结果 "Square root of 4.0 is 2.0"。 小结 本文介绍了Java中的Math类,包括定义、源代码解析、应用场景案例、优缺点分析、类代码方法介绍、测试用例等。Math类提供了一系列与数学计算相关的方法,可以方便地进行数学计算。但是,Math...
+double add(double a, double b)+double subtract(double a, double b)+double multiply(double a, double b)+double divide(double a, double b)+double squareRoot(double a)+static void main(String[] args) 结论 通过创建简单的计算器项目,我们展示了如何在 Java 中导入和使用Math类。该项目不仅增强了...
publicclassMathExample{publicstaticvoidmain(String[]args){// 绝对值函数:返回给定数值的绝对值intnegativeNumber=-10;intabsoluteValue=Math.abs(negativeNumber);System.out.println("绝对值: "+absoluteValue);// 输出:绝对值: 10// 幂函数:返回 x 的 y 次幂doublebase=2.0;doubleexponent=3.0;doublepower=M...
the positive square root of a. If the argument is NaN or less than zero, the result is NaN. cbrt public static double cbrt(double a) Returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negat...
double number = 25;double sqrtNum = Math.sqrt(number);System.out.println("Square root of " + number + " is " + sqrtNum); 3、取整(Rounding) double value = 3.6;long roundedValue = Math.round(value);System.out.println("Rounded value of " + value + " is " + roundedValue); ...
Example: Java Math sqrt() class Main { public static void main(String[] args) { // create a double variable double value1 = Double.POSITIVE_INFINITY; double value2 = 25.0; double value3 = -16; double value4 = 0.0; // square root of infinity System.out.println(Math.sqrt(value1))...
import java.util.Scanner;public class Test { public static void main(String[] args) { Scanner sca=new Scanner(System.in); int a=sca.nextInt(); int b=sca.nextInt(); int c=sca.nextInt(); MathUtil util=new MathUtil(); util.squareCut(a, b); util.oddSum(c); util.equationRoot(a...
the positive square root of a. If the argument is NaN or less than zero, the result is NaN. cbrt public static double cbrt(double a) Returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negat...
Number The square root of the number. NaN if the number negative. Related Pages: JavaScript Math JavaScript Numbers JavaScript Number Reference Browser Support Math. is an ECMAScript1 (JavaScript 1997) feature. It is supported in all browsers: Chrome Edge Firefox Safari Opera IE Yes Yes Yes Yes...
(diff))) == (int)(Math.Floor(Math.Sqrt(diff))) return true; }...return false; } private bool IsPerfectSquare(int num) { double sq1 = Math.Sqrt...(num); int sq2 = (int)Math.Sqrt(num); if (Math.Abs(sq1 - (double)sq2) < 10e-10)...= 0) { int t = (int)Math.Floor...