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(1) One Eigenvector Case X2(t) = K21temt + K22emt (5) (A-mI)K21temt + [(A-mI)K22 – K21]emt = 0 (6) Note that (6) will hold if: (A-mI)K21 = 0 (7) and (A-mI)K22 = K21 (8) Thus, if we take K21 to be an eigenvector of A corresponding to eigenvalue ...