epf+upf=D1(P*+T*).^D2 可见P*=-T*时混凝土材料不能产生塑性应变 弹性体积模量Kelastic=Pcrush/ucrush 所以能解释Pc=16MPa,uc=0.001,则K=16GPa 相关的格式如下: $*MAT_JOHNSON_HOLMQUIST_CONCRETE $mid ro, g, A B C N fc 1 0.26E+04 4.8E+9 0.79 1.6 0.007 0.61 48E6 $ T epsilon EFMIN...
大胸弟,这个材料要付给弹簧单元的,或者部分弹簧单元。你说的长方体肯定不行。
wheretheyieldstrengthcanbeusedasasingleparametertocharacterizemetalsofasimilarclass,e.g.steels,itneedstobenotedthattheyieldstrengthonlycharacterizestheelasticresponseofthemetal.Forconcretes,theunconfinedcompressivestrengthparameternotonlydescribestheelasticresponse,buttheinelastic(plastic)responseincludingtheshearfailure...
11 Superelastic stress as a function of temperature in different su- perelastic alloys[7] 目前, 有关 FeMnAlNi 系合金的研究方兴未艾, 由于 其超弹性良好, 超弹性温度范围大, 温度依赖性低, 成 本优势和工业生产优势巨大, 使该合金成为一种极具发 展潜力的超弹性合金. 目前的研究虽然已经取得一定进 展...
wheretheyieldstrengthcanbeusedasasingleparametertocharacterizemetalsofasimilarclass,e.g.steels,itneedstobenotedthattheyieldstrengthonlycharacterizestheelasticresponseofthemetal.Forconcretes,theunconfinedcompressivestrengthparameternotonlydescribestheelasticresponse,buttheinelastic(plastic)responseincludingtheshearfailure...
wheretheyieldstrengthcanbeusedasasingleparametertocharacterizemetalsofasimilarclass,e.g.steels,itneedstobenotedthattheyieldstrengthonlycharacterizestheelasticresponseofthemetal.Forconcretes,theunconfinedcompressivestrengthparameternotonlydescribestheelasticresponse,buttheinelastic(plastic)responseincludingtheshearfailure...