它确保数据将保持安全。 例如: #includeint main () {char *ptr;ptr = (char *) malloc(10);strcpy(ptr, "Programming");printf(" %s, Address = %un", ptr, ptr);ptr = (char *) realloc(ptr, 20); //ptr is reallocated with new sizestrcat(ptr, " In 'C'");printf(" %s, Address = ...
char name[50]; } Person; Person *person = malloc(sizeof(Person)); if (person != NULL) { person->id = 1; strcpy(person->name, "John Doe"); } Reallocating memory: realloc() is used to resize previously allocated memory blocks. 1int *arr = malloc(10 * sizeof(int)); 2if (...
在你的例子中，int_array只在定义它的函数执行还没有结束时存在，你不能在函数之间传递它。你不能返回...
Yes, the reason it doesn't work is because in C an array (eg. int v[]) is almost the same as a pointer (int *p), but the array is allocated on the stack and not on the heap. When you declare a vector int v[] = {0, 1, 2, 3, 4}, v is a pointer to the location in...
malloc_in_function.c 1#include <stdio.h>2#include <stdlib.h>345voidmalloc_in_function(char**myArray,intsize)6{7inti =0;89*myArray = (char*)malloc(size *sizeof(char));10if(*myArray ==NULL)11{12fprintf(stderr,"Error allocating memory for myArray!\n");13exit(0);14}1516/*this...
由于malloc函数返回值的类型是void *,也就是未确定类型的指针,它可以指向任何类型的数据,更直白地说就是在申请内存空间的时候,系统并不知道我们要用这块空间存储什么具体类型的数据(比如是char类型、int类型还是别的类型)。所以在 C++ 中,如果写成像p = malloc (sizeof(int));这样的代码,程序是无法通过编译的,...
例如,const char** array = /* ??? */。我知道malloc类似于C++中的new,但总是返回void*。更广泛地说,在C和C++中处理内存管理的方式有什么不同?例如,在C语言中,有哪些事情是人们在C++中可能没有考虑到的? 浏览5提问于2019-12-10得票数 1 回答已采纳 5回答 数组的用户输入大小 、 我试图编写一个程序...
C语言中的realloc函数将在新区域中复制所有先前的数据。它确保数据将保持安全。 例如: #includeint main () { char *ptr; ptr = (char *) malloc(10); strcpy(ptr, "Programming"); printf(" %s, Address = %un", ptr, ptr); ptr = (char *) realloc(ptr, 20); //ptr is reallocated with new...
// another array of 20 characters. if( i == 0 ) { char*AnotherArray =newchar[20]; } } delete[] AnotherArray;// Error: pointer out of scope. delete[] AnArray;// OK: pointer still in scope. } 在上面的示例中,指针 AnotherArray 一旦超出范围,将无法再删除对象。
void swap(struct Array* arr, int i, int j) { int temp = arr->data[i]; arr->data[i] = arr->data[j]; @@ -81,20 +57,19 @@ void quick_sort(struct Array* arr, int start, int end){ }; struct Array to_array(char cStr[]) { struct Array arr; char temp[strlen(cStr)], ...