Intuition For any operation, we need to pick the smallest possible element from the second array. So, we can start by sorting the second array. Solution Run the search with two branches: Keep the current element (if increasing), add an operation. Return the minimum of these branches. For ...
【leetcode】1187. Make Array Strictly Increasing 题目如下: Given two integer arraysarr1andarr2, return the minimum number of operations (possibly zero) needed to makearr1strictly increasing. In one operation, you can choose two indices0 <= i < arr1.lengthand0 <= j < arr2.lengthand do ...
链接:https://leetcode-cn.com/problems/remove-one-element-to-make-the-array-strictly-increasing这道题官方给的 tag 是简单题但是一点都不简单。题意是给一个数组,如果最多删除数组中的一个数字就能使得数组整体是单调递增的话,返回 true,否则返回 false。这道题我一开始做的时候切入点就不对,我想的一直是...
For example, ifnums = [1,2,3], you can choose to incrementnums[1]to makenums = [1,3,3]. Return the minimum number of operations needed to makenumsstrictly increasing. An arraynumsis strictly increasing ifnums[i] < nums[i+1]for all0 <= i < nums.length - 1. An array of lengt...
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如果做过O(n)的非降子序列,再把这道题转换过去,就会比较简单。 需要注意的是,到底是不是strictly increase 300题是要求strictly increase...
全部题解 题解不存在 请查看其他题解 C++ 智能模式 1 2 3 4 5 6 class Solution { public: bool canBeIncreasing(vector<int>& nums) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums = [1,2,10,5,7] 1 2 3 [1,2,10,5,7] [2,3,1,2] [1,1,1]...
1909. 删除一个元素使数组严格递增 - 给你一个下标从 0 开始的整数数组 nums ,如果 恰好 删除 一个 元素后,数组 严格递增 ,那么请你返回 true ,否则返回 false 。如果数组本身已经是严格递增的,请你也返回 true 。 数组 nums 是 严格递增 的定义为:对于任意下标的 1
1classSolution {2func makeArrayIncreasing(_ arr1: [Int], _ arr2: [Int]) ->Int {3let n1 =arr1.count4let s2 = Set<Int>(arr2)5vara3 =Array(s2)6a3 =a3.sorted()7let n3 =a3.count89vardp = [[Int]](repeating: [Int](repeating: Int.max/2, count: n3), count: n1)10vardp1 ...
链接:https://leetcode-cn.com/problems/remove-one-element-to-make-the-array-strictly-increasing/solution/bian-li-yi-bian-shu-zu-zhao-tuo-feng-huo-hvyd/ 来源:力扣(LeetCode) 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。