Intuition For any operation, we need to pick the smallest possible element from the second array. So, we can start by sorting the second array. Solution Run the search with two branches: Keep the current element (if increasing), add an operation. Return the minimum of these branches. For ...
https://leetcode.com/problems/make-array-strictly-increasing/ https://leetcode.com/problems/make-array-strictly-increasing/discuss/377403/Python-DP-solution-with-explanation. https://leetcode.com/problems/make-array-strictly-increasing/discuss/377680/Simple-Java-DP-Solution-%2B-TreeSet-with-Explanatio...
No resulting array is strictly increasing, so return false. Example 3: Input: nums = [1,1,1] Output: false Explanation: The result of removing any element is [1,1]. [1,1] is not strictly increasing, so return false. Constraints: 2 <= nums.length <= 1000 1 <= nums...
Given a 0-indexed integer array nums, return trueif it can be made strictly increasing after removing exactly one element, orfalseotherwise. If the array is already strictly increasing, returntrue. The array nums is stri...
1classSolution {2func makeArrayIncreasing(_ arr1: [Int], _ arr2: [Int]) ->Int {3let n1 =arr1.count4let s2 = Set<Int>(arr2)5vara3 =Array(s2)6a3 =a3.sorted()7let n3 =a3.count89vardp = [[Int]](repeating: [Int](repeating: Int.max/2, count: n3), count: n1)10vardp1 ...
【leetcode】1187. Make Array Strictly Increasing 题目如下: Given two integer arraysarr1andarr2, return the minimum number of operations (possibly zero) needed to makearr1strictly increasing. In one operation, you can choose two indices0 <= i < arr1.lengthand0 <= j < arr2.lengthand do ...
链接:https://leetcode-cn.com/problems/remove-one-element-to-make-the-array-strictly-increasing/solution/bian-li-yi-bian-shu-zu-zhao-tuo-feng-huo-hvyd/ 来源:力扣(LeetCode) 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。