根据该手册,可以配置LPm_divide.quartus自带的IP中除法器。可以配置为单时钟运行。或者多时钟运行。根据我的经验,要跑到到100M,需要20个时钟。 fpga verilog Ip核使用手册2018-10-18 上传大小:944KB 所需:48积分/C币 ug_lpm_rom.rar_ ug_lpm_rom_fpga LPM_rom vhdl_lpm rom m_quartus ...
My question is how to use the LPM_DIVIDE megafunction to do this? Let's say you have two fixed point binary numbers with 4 bit precision, like 1110.0010. If you use the megafunction, you will get a quotient and remainder. The problem is how do you convert these two outputs back ...
lpm_divide_component.lpm_hint = "LPM_REMAINDERPOSITIVE=TRUE", lpm_divide_component.lpm_nrepresentation = "SIGNED", lpm_divide_component.lpm_pipeline = 1, lpm_divide_component.lpm_type = "LPM_DIVIDE", lpm_divide_component.lpm_widthd = 16, lpm_divide_component.lpm_widthn = 31; endmodule /...
I'm working with an Arria II GX. I've been having timing issues with the lpm_divide megafunction. I have created a divider using the MegaWizard Plug-In Manager that has a Numerator of 64-bits (signed, FixedPoint) and a Denominator of 32-bits (signed, FixedPoint). I've been fighti...
lpm_divide Megafunction 用户使用手册 根据该手册,可以配置LPm_divide.quartus自带的IP中除法器。可以配置为单时钟运行。或者多时钟运行。根据我的经验,要跑到到100M,需要20个时钟。 上传者:tanianqingdi时间:2018-10-18 eda.rar_lpm_rom_累加器 直接数字频率 相位累加器 寄存器 lpm_rom ...
Error (272006): In lpm_divide megafunction, LPM_WIDTHN must be less than or equals to 64 Error (12154): Can't elaborate inferred hierarchy "system_soc:u0|Controller_for_SiemensMR_ip:controller_for_siemensmr_ip_0|Controller_for_Siemens...
You use Altera's megafunction to generate the "DIVIDER" wizard, now you will see like that follows: // megafunction wizard: %LPM_DIVIDE% // GENERATION: STANDARD // VERSION: WM1.0 // MODULE: lpm_divide // === // File Name: div31.v // Megafunction Name(s): // lpm_divide // ...