报错FloatingPointError: Loss became infinite or NaN at iteration=88!,程序员大本营,技术文章内容聚合第一站。
loss_dict = {'loss_fcos_cls': tensor(nan, device='cuda:0', grad_fn=<DivBackward0>), 'loss_fcos_loc': tensor(0.5552, device='cuda:0', grad_fn=<DivBackward0>), 'loss_fcos_ctr': tensor(0.7676, device='cuda:0', grad_fn=<DivBackward0>), 'loss_mask': tensor(0.8649, device='...
As the results, the optimizer update the NaN unscaled gradient to the network and finally cause the loss become NaN in the next iteration. scaler_unscale_grads() only check the scaled gradient is NaN or not, but in the above case, the problem lies in the unscaled gradient! pytorch/torch...
Search before asking I have searched the YOLOv5 issues and discussions and found no similar questions. Question When I use VisDrone dataset to train YOLOv5, after a few epoch, the loss becomes nan, and there is no prediction. Someone sai...
www.nature.com/scientificreports/ Figure 1. Comparison of confinement and loss properties of surface plasmon polaritons propagating on niobium (a, blue diagram), gold (b, green diagram) and silver (b, purple diagram), assuming that the metal films are sandwiched between two semi-infinite ...
Third, the medium is an infinite plane, hence the volume charge density of the system (ρ) can be replaced by a surface charge density (σ). Finally, the charge density is continuously generated, while resulting in the generation of an electric field (E) and causing the materials to be ...
In the network of [52], the data of an infinite number of nodes can be merged into one data packet when they meet, so the amount of data that the network needs to transmit is hardly increased. Thus, in the method of [52], each node routes during broadcast, and the receiver node ...
Because our loci do not appear to conform to the strict stepwise mutation model (SMM), we performed 5,000 iterations of the Wilcoxon signed-rank test with the infinite allele model (IAM) and two-phase mutation (TPM) model (90% stepwise and 10% multistep mutations; [64]). We tested ...
In [19], this corresponds to the case of an infinite wavelength where the assumed eddy-current paths are illustrated in Figure 2. From Figure 2, the flux in the assumed eddy-current path φ can be expressed as: yx φ = −y −x Bνm sin (ωνm t) dxdy. (4) The losses in ...