我自己居然能做出来了。 importjava.util.Scanner;publicclassAbc229{publicstaticvoidmain(String[]args){Scanner sc=newScanner(System.in);String s=sc.next();int n=s.length();int k=sc.nextInt();int cnt=0;int max=0;int l=0;int
classSolution{ publicintfindTheLongestSubstring(String s){ intres=0; intcur=0; intn=s.length(); HashMap<Integer, Integer> map =newHashMap<>(); map.put(0, -1); for(inti=0; i < n; i++) { charch=s.charAt(i); if(ch =='a') { cur ^= (1<<1); }elseif(ch =='e') ...
Given an array A of N elements integer number. N can be up to 200000. Each element A[i] ranges from -1e9 to 1e9, no element equals to Zero (0). We define a "valid" sequence such that1. {x, -x} is valid sequence.2. {x, S, -x} is valid sequence if S is a valid seq...
The first line of input contains an integer T (≤ 60). Each of the next T lines is a string, whose length is always less than 1000. For ≥ 90% of the test cases, string length ≤ 255. Output For each input string, your program should print the length of the longest palindrome you...
The first line there are two integers N and M in the first line (1 <= N, M <= 100000), and the second line contains N integers card[i] (0 <= card[i] <= M). Output For each test case, output a single integer in a line -- the longest straight ZB can get. ...
A method and apparatus for determining a longest prefix match in a segmented content addressable memory (CAM) device. The CAM device includes multiple CAM array blocks that each may be arbitrarily loaded with CIDR addresses. For one embodiment, each CAM array is a ternary CAM array that includes...
Input: String P = p1 ··· pr, integer k and character ch Output: σ(P [1 : k] ⊕ ch) 1: while k ≥ 0 pk+1 = ch do 2: k ← kmp(k) 3: end while 4: return k + 1 Algorithm 4 λ(k, ch). Input: Integer k, character ch Output: Value of λ(k, ch) 1: if k ...
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Each of the next n lines contains a single string t. It is guaranteed that every t contains each of the first k upper-case letters of the alphabet exactly once. 输出 Output a single integer, the length of the longest subsequence that appears in all n strings. ...
String longestCommonPrefix_4(String[] strs) { if (strs == null || strs.length == 0) return ""; int minLen = Integer.MAX_VALUE; for (String str : strs) minLen = Math.min(minLen, str.length()); int low = 1; int high